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What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How many grams of hydrogen are in 5.60 moles of methane?
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
How many molecules in 10 grams of methane?
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
How many C2H4 molecules are contained in 45.8 mg of C2H4?
To determine the number of molecules in 45.8 mg of C2H4, we first calculate the number of moles using the molar mass of C2H4 (28.05 g/mol). Then we use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules, which is approximately 1.23 x 10^20 molecules.
How many moles are present in 2.45 molecules of CH4?
To find moles, simply divide the number of representative particles (in this case, molecules of methane) by Avogadro's number (6.02x1023.)2.45x1023/6.02x1023 = approx. 0.41 moles (the exponents cancel out.)
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How many grams of hydrogen are in 5.60 moles of methane?
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
If 5.0 moles of C3H8 react how many molecules of water are formed?
For every mole of C3H8 that reacts, 4 moles of water are formed. Therefore, 5.0 moles of C3H8 will form 5.0 x 4 = 20 moles of water. To convert moles to molecules, you would then multiply by Avogadro's number (6.022 x 10^23 molecules/mol). So, 20 moles of water would equal 20 x 6.022 x 10^23 = 1.2044 x 10^25 molecules of water.
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
How many moles of He are 1.201025 atoms He?
20 moles
How many molecules in 10 grams of methane?
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
How many' O' molecules are in o.20 mol C6H12O6?
0.2 moles C6H12O6 x 6.02x10^23 molecules/mole = 1.2x10^23 molecules of C6H12)61.2x10^23 molecules C6H12O6 x 6 molecules "O"/molecule C6H12O6 = 7.2x19^23 molecules "O"
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many C2H4 molecules are contained in 45.8 mg of C2H4?
To determine the number of molecules in 45.8 mg of C2H4, we first calculate the number of moles using the molar mass of C2H4 (28.05 g/mol). Then we use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules, which is approximately 1.23 x 10^20 molecules.
How many atoms in 3CH4?
There are 16 atoms in 3CH4, which consists of 3 molecules of methane (CH4). Each methane molecule contains 5 atoms - one carbon atom and four hydrogen atoms. So, 3 molecules of CH4 contain a total of 3 carbon atoms and 12 hydrogen atoms, giving a total of 16 atoms.
Does 10o2 plus 10H2 make 20 moles of water?
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
