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How many moles are contained in 8.08 L of O2 at standard temperature and pressure?
1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP). Therefore, 8.08 L of O2 at STP would contain 8.08/22.4 = 0.36 moles of O2.
What is the chemical equation shows the formation of water from hydrogen and oxygen?
The chemical equation for the formation of water from hydrogen and oxygen is: 2H2 + O2 → 2H2O. This equation shows that two molecules of hydrogen gas (H2) react with one molecule of oxygen gas (O2) to form two molecules of water (H2O).
What is the chemical equation of hydrogen combustion?
The chemical equation for hydrogen combustion is 2H2 (g) + O2 (g) -> 2H2O (l). This means that two molecules of hydrogen gas react with one molecule of oxygen gas to form two molecules of water.
How many grams of FeO2 can be produced from 50.0 L of O2 at STP?
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
How many moles of MgO are produced from 11.2 L O2?
To determine the number of moles of MgO produced from 11.2 L of O2, you would first need to balance the chemical equation for the reaction involving MgO and O2. Then, using the ideal gas law and stoichiometry, you can calculate the moles of MgO produced.
What is mass and no of molecules of O2 having volume 22.4 dm3?
22,4 L is the molar volume. 1 mol of oxygen has 32 g and and 6,022140857.10e23 molecules.
How many moles are contained in 8.08 L of O2 at standard temperature and pressure?
1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP). Therefore, 8.08 L of O2 at STP would contain 8.08/22.4 = 0.36 moles of O2.
How many molecules of O2 ar needed in the chemical formula for burning methane?
You should set up a balanced equation for the combustion of CH4 first: CH4 + 2 O2 --> CO2 + 2 H2O Now you see that for every 1 mole of CH4 you have 2 moles of O2. Therefore if you have 2.67 L of CH4, you'll have 5.34 L of O2. You can also assume it's at STP just to check, since it all cancels out in the end: 2.67L CH4 (1mol CH4/22.4L)(2mol O2/ 1 mol CH4)(22.4L/1mol O2)= 5.34L O2.
What is the chemical equation shows the formation of water from hydrogen and oxygen?
The chemical equation for the formation of water from hydrogen and oxygen is: 2H2 + O2 → 2H2O. This equation shows that two molecules of hydrogen gas (H2) react with one molecule of oxygen gas (O2) to form two molecules of water (H2O).
What is the chemical equation of hydrogen combustion?
The chemical equation for hydrogen combustion is 2H2 (g) + O2 (g) -> 2H2O (l). This means that two molecules of hydrogen gas react with one molecule of oxygen gas to form two molecules of water.
How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
How many o2 sensors are there on a 01 Chevy s10?
2 if it has the 2.2 L engine, 3 if it has the 4.3 L engine.
How many moles are contained in 5.33 L of O2 at standard temperature and pressure?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of O2 in 5.33 L, you can use the formula: moles = volume (L) / molar volume (L/mol). Thus, moles of O2 = 5.33 L / 22.4 L/mol, which is approximately 0.238 moles.
How many oxygen molecules are in 9.1 L of oxygen gas at STP?
at stp 1 mole of a gas contains 22.4 litres. 9.1/22.4= .40625 moles o2. 1 mole of a gas contains 6.022E23 molecules so .40625 moles x 6.022E23 = 2.4464325E23 molecules, but you have to multiply by two due to it being diatomic, so answer x 2 = 4.892875E23 molecules
How many grams of FeO2 can be produced from 50.0 L of O2 at STP?
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
The balanced equation for the decomposition of hydrogen peroxide?
One molecule of Oxygen Gas (O2) combines with two molecules of Hydrogen Gas (2H2) to form two molecules of water 2H2O. O2+2H2=> 2H2O There are the same numbers of H's and O's either side of the = meaning the equation is balanced, in respect of the fact that Oxygen and Hydrogen Gas have diatomic molecules (2 atoms stick together)
How many moles of MgO are produced from 11.2 L O2?
To determine the number of moles of MgO produced from 11.2 L of O2, you would first need to balance the chemical equation for the reaction involving MgO and O2. Then, using the ideal gas law and stoichiometry, you can calculate the moles of MgO produced.
