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How many oxygen molecules are there in in 4 g of oxygen?
Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
How many liters of oxygen gas are present in 11.3 grams of oxygen gas?
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
What is the STP for Oxygen?
Standard temperature and pressure (STP) for oxygen is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals). At STP, one mole of oxygen gas occupies a volume of 22.4 liters.
A 2.50 liter sample of a colorless gas at STP decomposed to give 2.50 liters of nitrogen gas and 1.25 liters of oxygen at STP. what is the colorless gas?
The colorless gas is likely nitrous oxide (N2O) because it decomposed into nitrogen gas and oxygen gas, which are the components of nitrous oxide. The balanced chemical equation for the reaction is 2N2O -> 2N2 + O2.
How many moles and how many molecules are in 64 g of oxygen gas?
1 mole O2 weighs 32 gso 64 g O2 is 2 mol O2 gaswhich has 2 X 6.022 X 1023 = 1.2066 X 1024 molecules of O2
How many moles of o2 molecules are there in 50dm3 of o2 gas at STP?
A cubic decimeter is a liter, so we're talking 50L of oxygen gas at STP. 1mol of any gas at STP occupies 22.4L of space, so 50/22.4 = about 2.2mol of oxygen.
How many moles are in 68.5 liters of oxygen gas at STP?
1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP). Therefore, 68.5 liters of oxygen gas at STP would be 68.5/22.4 = 3.06 moles of oxygen gas.
How many oxygen molecules are present in 113.97 liters of oxygen gas at STP?
At STP, one mole of any gas occupies 22.4 liters. This is called molar volume. 113.97 liters ÷ (22.4 L/mol) = 5.09 moles Then convert moles to molecules (1 mole = 6.02 × 1023 molecules) 5.09 moles × (6.02 × 1023 molecules/mol) = 3.06 × 1024 molecules
In a sample of oxygen gas at stp which represents the greatest number of molecules?
The gas sample that has the greatest number of molecules is the one with the largest amount of substance, which is measured in moles. At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. Therefore, the gas sample with the largest volume at STP will have the greatest number of molecules.
What type of element of oxygen?
A gas at STP.
Oxygen is what type of element?
part of the oxygen group....gas, nonmetal...
How many butane molecules are in 22.4 liters of C4H10 gas at STP?
There are 6.02 x 10^23 molecules in one mole of a substance (Avogadro's number). At STP, 22.4 liters of any ideal gas contains 1 mole of gas. Therefore, there are 6.02 x 10^23 butane molecules in 22.4 liters of C4H10 gas at STP.
Why some oxygen dissolved in water?
Like most diatomic gas molecules oxygen will not dissolve very well in water (less than 10 mg/L at STP).
One liter of oxygen at NTP contains?
One liter of oxygen (O2) gas at standard temperature and pressure (STP) \ill contain 1/22.4 of a mole of molecules. STP is defined as 0 degrees Celsius at 1 atm of pressure.
Is fluorine a monatomic gas at STP?
No, fluorine is a diatomic gas at standard temperature and pressure (STP), meaning it exists as F2 molecules, not as single F atoms.
How many grams of oxygen gas is contained in 11.2L 02 gas at stp?
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Since 11.2 liters represent half the volume of a mole, we have 0.5 moles of O2 gas. Using the molar mass of oxygen (O2), which is around 32 g/mol, we find that 0.5 moles of O2 gas would be equivalent to approximately 16 grams.
How many liters are in 5.4x1024 molecules of nitric oxide at STP?
Using the ideal gas law (PV = nRT), we can calculate the volume of gas at STP. First, we need to convert the number of molecules to moles by dividing by Avogadro's number. Then, we can use the volume of 1 mole of gas at STP, which is 22.4 liters. Calculate V = (5.4x10^24 / 6.022x10^23) * 22.4 to find the volume in liters.
