STP is the same for all gasses an gaseous mixtures: 0 degrees Celsius at a prssure of 1 atm.
at stp 1 mole of a gas contains 22.4 litres. 9.1/22.4= .40625 moles o2. 1 mole of a gas contains 6.022E23 molecules so .40625 moles x 6.022E23 = 2.4464325E23 molecules, but you have to multiply by two due to it being diatomic, so answer x 2 = 4.892875E23 molecules
Arguably, none. But oxygen exists in 2 forms at STP - O2 and O3 - ozone.
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
The colorless gas is likely nitrous oxide (N2O) because it decomposed into nitrogen gas and oxygen gas, which are the components of nitrous oxide. The balanced chemical equation for the reaction is 2N2O -> 2N2 + O2.
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
hydrogen, nitrogen, oxygen, fluorine, and chlorine are all gases at STP
A gas at STP.
1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP). Therefore, 68.5 liters of oxygen gas at STP would be 68.5/22.4 = 3.06 moles of oxygen gas.
part of the oxygen group....gas, nonmetal...
They are both elements, they are both gases at STP.
The average distance between oxygen molecules at Standard Temperature and Pressure (STP) is approximately 3.3 nanometers.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 15 liters of oxygen at STP would be equivalent to 15/22.4 = 0.67 moles.
5600 mL
Oxygen is typically found in the gaseous state at room temperature and pressure.
One mole of any gas at STP occupies 22.4 liters. Therefore, one mole of oxygen gas at STP also occupies 22.4 liters.
Oxygen is boiling at 90.20 K (-182.95 °C) when at STP
The volume is 64,8 L.