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How many liters of oxygen gas are present in 11.3 grams of oxygen gas?
Wiki User
∙ 14y ago
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
Wiki User
∙ 14y ago
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