Moler mass of CH4O :32.05
32gof CH4O*(1molofCH4O/32.05 CH4O)*6.02*10^23
There are 4 hydrogen atoms in CH4O
Methane monoxide
There are three different elements in the molecule CH4O: Carbon (C), Hydrogen (H), and Oxygen (O).
There are 6 atoms in CH4O: 1 carbon (C) atom, 4 hydrogen (H) atoms, and 1 oxygen (O) atom.
In CH4O, there are 14 valence electrons: 4 from carbon, 1 from hydrogen, and 6 from oxygen.
There are 4 hydrogen atoms in CH4O
32g increased by 8% = 34.56g = 32g + (8% * 32g) = 32g + (0.08 * 32g) = 32g + 2.56g = 34.56g
Methane monoxide
There are three different elements in the molecule CH4O: Carbon (C), Hydrogen (H), and Oxygen (O).
There are 6 atoms in CH4O: 1 carbon (C) atom, 4 hydrogen (H) atoms, and 1 oxygen (O) atom.
For this you need the atomic (molecular) mass of CH4O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CH4O=32.0 grams.998 grams CH4O / (32.0 grams) =.0312 moles CH4O
In CH4O, there are 14 valence electrons: 4 from carbon, 1 from hydrogen, and 6 from oxygen.
Methanol and water can be mixed to any proportion without trouble.
32g. You already knew the answer stupid.
First figure the molar mass for each...C2H6O=46 & CH4O=32. Together C2H6O(46)+CH4O(32)= 78 Now you take molar mass / total molar mass So C2H6O(46)/total mass (C2H6O+CH4O)78= C2H60 or ethanol=0.410 and CH4O(32)/total mass 78=CH4O or methanol=0.589
Methanol, CH3OH (CH4O) is a covalent molecular compound. It is liquid under normal conditions and there is hydrogen bonding between molecules
No. CH4O is molecular. Specifically it is an alcohol.