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How many molecules of o2 are present in 1l air containing 80 percent volume of o2 at stp?
Wiki User
∙ 12y ago
Please check the workings if you wish to understand how the problem is solved.
At S.T.P.,
1 mole of any gas = 22.4 Litres(It's a given. I assume you know this one.)
Therefore,
1 Litre of a gas = 1/22.4 = 0.0446 moles
Out of these 0.0446 moles, 80% is Oxygen gas.
Number of moles of Oxygen gas = 0.0446 x 80% = 0.0446 x 80/100 = 0.0357 moles.
1 mole of any gas = 6.02 x 1023 units (This is also a given, known as the Avagadro's constant.)
Therefore,
0.0357 moles = 0.0357 x 6.02 x 1023 = 2.15 x 1022 molecules of Oxygen gas.
Wiki User
∙ 12y ago
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