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No problem - first, get the formula for aluminum chromate. The chromate polyatomic ion is CrO4 with a -2 charge. Aluminum has 3 valence electrons, so when it bonds with the chromate poly, the formula must be Al2(CrO4)3. Now, use the Periodic Table to get the molar mass for that formula unit. 2 aluminums, 3 chromiums, and 12 oxygens are 2(27)+3(52)+12(16)=402 grams/mole. You have 3.3 kg, which is 3,300g. Set up a direct proportion: 402g/1mol=3,300g/"x" moles. Solve for "x" to get approx. 8.21 moles of aluminum chromate.
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