To calculate the number of moles, we divide the number of atoms by Avogadro's number, which is 6.022 x 10^23. In this case, 2.4 x 10^24 atoms of He divided by 6.022 x 10^23 atoms/mole is equal to approximately 4 moles of He.
To find the number of moles in 3.6 x 10^24 atoms of chromium, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). 3.6 x 10^24 atoms of Cr / 6.022 x 10^23 atoms/mol ≈ 5.98 moles of Cr.
There are approximately 1.81 x 10^24 atoms in 3.00 moles of sodium. This can be calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
To calculate the number of moles from the number of atoms, we need to divide the number of atoms by Avogadro's number (6.022 × 10^23), which gives 3.59 moles of iron atoms.
3,00 moles of Li have 18,066422571.10e23 atoms.
To find the number of moles in 3.6 x 10^24 atoms of chromium, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). 3.6 x 10^24 atoms of Cr / 6.022 x 10^23 atoms/mol ≈ 5.98 moles of Cr.
There are approximately 1.81 x 10^24 atoms in 3.00 moles of sodium. This can be calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
In a mole there is 6.022 x 1023 atoms. In two moles there are twice that amount.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
To find the number of moles in (1.63 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Divide the number of atoms by Avogadro's number: [ \text{moles} = \frac{1.63 \times 10^{24}}{6.022 \times 10^{23}} \approx 2.71 \text{ moles}. ] Thus, there are approximately 2.71 moles in (1.63 \times 10^{24}) atoms.
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
There are approximately 2.8 x 10^24 atoms in 4.7 moles of helium. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mole) by the number of moles (4.7).
To calculate the number of moles from the number of atoms, we need to divide the number of atoms by Avogadro's number (6.022 × 10^23), which gives 3.59 moles of iron atoms.
3,00 moles of Li have 18,066422571.10e23 atoms.
There are 24 moles of hydrogen in 4 moles of CH4 because each molecule of CH4 contains 4 hydrogen atoms. Therefore, you have 24 moles x 6.022 x 10^23 atoms/mol = 1.4448 x 10^25 atoms of hydrogen.
12.044x10^[24] atoms
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)