1.81x10^24 atoms
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
C6H1206 has 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms, otherwise known as Glucose, a plant food made for long-term storage. Sorry if that's not what you're looking for! Added: This is what you are looking for. 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 mole C/1 mole C6H12O6)(6.022 X 10^23/1 mole C)(1 mole C/6.022 X 10^23) = 9.99 moles Carbon atoms in that mass glucose 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(12 mole H/1 mole C6H12O6)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 19.98 moles Hydrogen atoms in that mass glucose Now, you have seen two examples of this procedure, so you do the oxygen number crunching.
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
300 g sulfur is equivalent to 9,357 moles.
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To find the number of moles, use the formula: moles = Molarity (M) x Volume (L). First, convert 300 ml to liters by dividing by 1000: 300 ml / 1000 = 0.3 L. Then, calculate moles = 1.5 M x 0.3 L = 0.45 moles. Therefore, there would be 0.45 moles in 300 ml of a 1.5 M solution.
1 mol = 6,022 x 10^23 molecules of HI. So: 6,022E23 *0,3 = Your answer !
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.
C6H1206 has 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms, otherwise known as Glucose, a plant food made for long-term storage. Sorry if that's not what you're looking for! Added: This is what you are looking for. 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 mole C/1 mole C6H12O6)(6.022 X 10^23/1 mole C)(1 mole C/6.022 X 10^23) = 9.99 moles Carbon atoms in that mass glucose 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(12 mole H/1 mole C6H12O6)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 19.98 moles Hydrogen atoms in that mass glucose Now, you have seen two examples of this procedure, so you do the oxygen number crunching.
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.