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How many moles is 573.28g of AgCl?
There's 4 moles.
How many moles are there in 28.4 g of cholrine atom?
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
How many moles of Na Cl could be made by combining 20000 mole of Na with 2 moles of Cl?
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
How many moles is 573.28 g of AgCl?
To find the number of moles, divide the given mass of AgCl by its molar mass. The molar mass of AgCl is 143.32 g/mol (107.87 g/mol for Ag + 35.45 g/mol for Cl). Therefore, 573.28 g ÷ 143.32 g/mol = 4 moles of AgCl.
How many grams of Cl are in 435 g of CaCl2?
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg plus 2ions?
0,5 moles Cl-
What is 2 Ag Cl?
2 Ag Cl refers to two moles of silver chloride, a chemical compound with the formula AgCl. It consists of one silver (Ag) ion and one chloride (Cl) ion, and is commonly used in photography and as a precursor in the production of silver compounds. Silver chloride is known for its low solubility in water and is often used in experiments involving silver ions.
How many moles is 573.28g of AgCl?
There's 4 moles.
How many moles of Cl are in a sample that contains 10.0 moles C2HCl3?
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg 2 ions?
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
How many moles are there in 28.4 g of cholrine atom?
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
How many moles of Na Cl could be made by combining 20000 mole of Na with 2 moles of Cl?
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
How many moles is 573.28 g of AgCl?
To find the number of moles, divide the given mass of AgCl by its molar mass. The molar mass of AgCl is 143.32 g/mol (107.87 g/mol for Ag + 35.45 g/mol for Cl). Therefore, 573.28 g ÷ 143.32 g/mol = 4 moles of AgCl.
How many grams of Cl are in 435 g of CaCl2?
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
Is Ag Cl soluble?
slightly
How many grams are in 3.5 moles of CL?
To find the mass in grams of 3.5 moles of chlorine (Cl), you can use the molar mass of chlorine, which is approximately 35.45 grams/mole. Multiply the number of moles by the molar mass: 3.5 moles × 35.45 g/mole = 124.575 grams. Therefore, there are approximately 124.58 grams in 3.5 moles of Cl.
How many atoms are in the molecule AgCl?
in the AgCl molecule two atoms present one is Ag (i.e.Ag in +1oxidation state) & another is Cl atom(Cl in -1).
