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How many moles is 573.28g of AgCl?
There's 4 moles.
How many moles are there in 28.4 g of cholrine atom?
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
How many moles of Na Cl could be made by combining 20000 mole of Na with 2 moles of Cl?
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
How many moles is 573.28 g of AgCl?
To find the number of moles, divide the given mass of AgCl by its molar mass. The molar mass of AgCl is 143.32 g/mol (107.87 g/mol for Ag + 35.45 g/mol for Cl). Therefore, 573.28 g ÷ 143.32 g/mol = 4 moles of AgCl.
How many grams of Cl are in 435 g of CaCl2?
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg plus 2ions?
0,5 moles Cl-
How many moles is 573.28g of AgCl?
There's 4 moles.
How many moles of Cl are in a sample that contains 10.0 moles C2HCl3?
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg 2 ions?
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
How many moles are there in 28.4 g of cholrine atom?
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
How many moles of Na Cl could be made by combining 20000 mole of Na with 2 moles of Cl?
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
How many moles is 573.28 g of AgCl?
To find the number of moles, divide the given mass of AgCl by its molar mass. The molar mass of AgCl is 143.32 g/mol (107.87 g/mol for Ag + 35.45 g/mol for Cl). Therefore, 573.28 g ÷ 143.32 g/mol = 4 moles of AgCl.
How many grams of Cl are in 435 g of CaCl2?
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
Is Ag Cl soluble?
slightly
How many atoms are in the molecule AgCl?
in the AgCl molecule two atoms present one is Ag (i.e.Ag in +1oxidation state) & another is Cl atom(Cl in -1).
How many moles of PCl3 contain 3.68 1025 chlorine atoms?
To find the number of moles of PCl3, you need to first calculate the number of moles of Cl atoms in 3.68 * 10^25 atoms. There are 3 Cl atoms in each molecule of PCl3, so you divide the number of Cl atoms by 3 to get the number of moles of PCl3.
How many Moles is 573.28 of Ag Cl?
To calculate the number of moles of silver chloride (AgCl), you need to know its molar mass. The molar mass of AgCl is approximately 143.32 g/mol. To find the number of moles in 573.28 grams of AgCl, you can use the formula: moles = mass (g) / molar mass (g/mol). Thus, 573.28 g of AgCl is approximately 4.00 moles (573.28 g ÷ 143.32 g/mol ≈ 4.00 moles).
