The answer is 0,123 mol.
There are 4.17 moles of H2O present in 75.0g of H2O.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
To find the number of moles in 317.0 g of Ba(OH)2, first calculate the molar mass of Ba(OH)2 which is 171.34 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, the number of moles would be 317.0 g / 171.34 g/mol ≈ 1.85 moles.
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To determine the number of moles in a solution, multiply the molarity (in moles per liter) by the volume of the solution (in liters). This calculation gives you the amount of substance in moles present in the solution.
To calculate the number of moles of Ba(OH)2 present in 125 mL of 8.00 M Ba(OH)2 solution, you can use the formula: moles = molarity x volume (in liters). First, convert 125 mL to liters (0.125 L), then multiply 8.00 M by 0.125 L to get 1.00 moles of Ba(OH)2.
There are 4.17 moles of H2O present in 75.0g of H2O.
The answer is 0,615 moles.
The answer is 8,33 moles.
The answer is 14,93 moles.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
.400 moles
If 17,4 is grams the number of moles is 0,084.
9.991 Moles (water) 8.982 Moles (heavy water)
5,7 moles (SO4)3-.
To find the number of moles in 317.0 g of Ba(OH)2, first calculate the molar mass of Ba(OH)2 which is 171.34 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, the number of moles would be 317.0 g / 171.34 g/mol ≈ 1.85 moles.
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