The answer is 0,123 mol.
14.59
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
5 moles
0.01362 moles.
44 moles of atoms
14.59
The "8.00 M Ba(OH)2" means 1 L of that solution contains 8.00 mol Ba(OH)2. 125 mL x 1 L x 8.00 mol Ba(OH)2 = 1.00 mol Ba(OH)2 ...........1000 mL ........ 1 L
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
5 moles
0.01362 moles.
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
The answer is 0,615 moles.
The answer is 8,33 moles.
44 moles of atoms
There are 10 moles present in 585 g of sodium chloride.
4.2 moles of CS2 contain 8,4 moles sulfur.
The answer is 14,93 moles.