Divide 96 by molecular mass.So the answer is 6mol
1 mole CH4 = 16.042g CH4
96g CH4 x 1mol CH4/16.042g CH4 = 6.0 moles CH4 (rounded to two significant figures)
Simply multiply by molecular mass. 16*6.So the mass produced is 96g
Divide mass by molecular mass.640/16.So the answer is 40
Divide 96 by molecular mass.So the answer is 6mol
Divide mass by molecular mass.So the answer is 3
Molar mass CH4 = 16.0 g/mole6.07 g x 1 mole/16.0 g = 0.379 moles (to 3 significant figures)
4 moles of ch4
6 mols
One molecule has four H atoms.So two moles have 8 moles
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
One molecule has four H atoms.So two moles have 8 moles
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
4.66715966 × 1024
First divide 6.25 by 16.Then moltiply by avagadro constant 6.02 × 10 23
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
It depends on temperature,pressure and volume.THese are needed to find number of moles
There are 0.75 moles in it.You have to devide 12 by molecular mass
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================