How many moles of CO2 are contained in 9.55l at 45C and 752torr?

Answer 1

First, some conversions: 45 deg. C. is 318 kelvins; 752 torr = 0.989atm. Now, use PV=nRT, with R=0.082: (0.989)(9.55)=n(0.082)(318); solve for n to get about 0.36mol.

Answer 2

From the combined gas law of PV = nRT we can solve for moles (n). n = PV/RT = (752 torr)(9.55 L)/62.36 L-torr/deg-mol)(318ºK) = 0.36 moles (2 sig figs)

Answer 3

The number moles is 0,36.