0
To convert grams to moles you use the molar mass of iron (55.8 grams per mole). Divide the numbers to get the number of moles: 500 g Fe / 55.8 g/mol = 8.96 mol Fe. To calculate the number of atoms, use Avogadro's Number (6.02*1023). Multiply the number of moles and Avogadro's number: 8.96 mol * (6.02*1023) = 5.39*1024 Fe atoms.
Wiki User
∙ 11y ago
Wiki User
∙ 9y agomoles=mass/mr of a substance
0.500=mass/2[55.8]+3[16]
0.500=mass/111.6+48
0.500.159.6=mass
mass=79.8g
Wiki User
∙ 12y ago150.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams)
= 0.9393 moles or iron(III)oxide
Wiki User
∙ 8y agoThe answer is o,156 mol.
Wiki User
∙ 7y agoThe answer is 2,507 moles iron.
Add your answer:
Earn +20 pts
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
How many moles of fe2o3 are in 217g of the compound?
1.358
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
If 4.00 kg of Fe2O3 are available to react how many moles of CO are needed and how many moles of each product are formed?
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
How many moles of Fe2O3 are in 251 g of the compound?
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
How many moles of Fe2O3 are in 231 g of the compound?
231 g of Fe2O3 are equal to 0,69 moles.
How many moles of Fe are present in 30 grams in rust?
This amount may be different because rust is not a clearly definite compound.
How many moles of Fe3O4 are needed to prepare 4.74 moles of Fe2O3?
7.18
How many moles of fe2o3 are in 217g of the compound?
1.358
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
How many Fe atoms are in 0.25 moles of Fe?
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
If 4.00 kg of Fe2O3 are available to react how many moles of CO are needed and how many moles of each product are formed?
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
How many moles of Fe2O3 are in 251 g of the compound?
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
How many moles of iron can be produced from the reaction of 10 mol Fe2O3 and 25 mol of CO?
17
How many moles of fe3o4 are needed to prepare 4.05moles of fe2o3?
Fe3O4 is not a pure compound...it is a mixture of FeO and Fe2O3 Assuming 100% yield in converting to all Fe2O3 4.05 mole x 2/3 = 2.7 mole
How many moles are present in 1.64g of MgSO4?
0.01362 moles.
