0.1 mols of N2 * 3 mols of H3/1 mol of N2
In other words, for 0.1 mols of N2 times 3 mols of H3 for ever mol of N2.
I order to find the other numbers you are going to need a balanced equation:
N2+3H2→ 2NH3
So you would have 0.3 mols.
Well this a difficult question. It depends what you are making, there are over 20 binary compoundsno nitrogen and hydrogen. The best known of which is ammonia, NH3 but others include hydrazine, N2H4 triazine N3H5.
As an example in the reaction of N2 with H2 to form ammonia.
N2 + 3H2 -> 2NH3
If you take two moles of nitrogen then you will need 6 moles of hydrogen.
To form NH3, I assume.
Balanced equation.
N2 + 3H2 -> 2NH3
0.85 moles N2 (3 moles H2/1 mole N2)
= 2.6 moles hydrogen gas needed
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If ammonia is being made
1.5 moles H2.
N2 + 3(H2) = 2NH3
Two moles of nitrogen are needed.
2 moles
2 moles
1
13
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
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The number of formula units is 0,602 214 085 7.10e23.
13
.085 meters
Approx. 11 400 km (ca. 7 085 miles)
1, 5, 17, 85
It is rational.
0.0851
http://www.goodanswers.com/hffl.085/related:crp,euphorbialacteachrist..:lect http://www.goodanswers.com/hffl.085/related:crp,euphorbialacteachrist..:lect
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.085 is a decimal number equivalent to a fraction. The expression 'whole numbers' refers to positive integers including zero :- 0,1,2,3,4, and so on. .085 can be expressed as a fraction 85/1000 which can be simplified to 17/200
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