Oh, dude, let's break it down. So, first off, you gotta calculate the molar mass of Na2CrO4, which is around 205.99 g/mol. Then, you divide the given mass by the molar mass to find the moles. In this case, 74.3 g / 205.99 g/mol gives you approximately 0.36 moles of Na2CrO4. So, there you have it, like, around 0.36 moles of that stuff in 74.3 grams.
To find the number of moles of Na2CrO4 in 74.3 grams, you need to divide the given mass by the molar mass of Na2CrO4. The molar mass of Na2CrO4 is calculated by adding the atomic masses of all the elements: 2(Na) + Cr + 4(O). Then divide 74.3 grams by the molar mass of Na2CrO4 to get the number of moles.
Assuming you mean 2.00 M and not 2.00 m, then moles of sodium chromate would be as follows:1.75 L x 2.00 moles/L = 3.50 moles sodium chromate
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. Therefore, 0.736 moles of H2SO4 is equal to 0.736 * 98.08 = 72.16 grams.
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
To find the number of moles of Na2CrO4 in 74.3 grams, you need to divide the given mass by the molar mass of Na2CrO4. The molar mass of Na2CrO4 is calculated by adding the atomic masses of all the elements: 2(Na) + Cr + 4(O). Then divide 74.3 grams by the molar mass of Na2CrO4 to get the number of moles.
If 2 moles of Na2CrO4 react completely, they will form the same number of moles of NaCl. This is because the mole ratio between Na2CrO4 and NaCl is 1:2. Therefore, 2 moles of Na2CrO4 will form 2 moles of NaCl.
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
Assuming you mean 2.00 M and not 2.00 m, then moles of sodium chromate would be as follows:1.75 L x 2.00 moles/L = 3.50 moles sodium chromate
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.
The molar mass of a compound is expressed in grams.
This depends on the compound.
0,27 moles of calcium contain 10,82 g calcium.
This depends on the compound.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
Multiply the number of moles by the molecular weight of the compound (or atomic weight for an element) to find the mass in grams.
number of moles = mass of the material/molar mass