Dry ice is the solid form of Carbon Dioxide ( chemical formula : CO2 ) , comprising two oxygen atoms bonded to a single carbon atom . It is colorless , odourless , non - flammable , and slightly acidic. It is commonly used as a versatile cooling agent .
Dry ice is the solid form of carbon dioxide. CO2 has a molar mass of 44.0095 grams per mol, so there are .227 moles present.
Ethanol C2H4O2 molar weight 60 grams/mole.
10grams/60grams/mole = .167 moles of ethanol as there are 2 Carbons per molecule of ethanol then there are .334 moles of Carbon.
This element is carbon.
10gI x (1 moleI / 126.9gI) = 0.079 molesI 2 significant figures.
No. of moles = mass/relitive molecular mass in this case = 10/16 = 0.625 so that's 0.625 of a mole and a mole of anything contains 6.022 x 1023 atoms = 3.76 x 1023 atoms in 10g of oxygen.
Step 1: balanced equation for the synthesis of ammonia:N2 + 3H2 --> 2NH3Step 2: convert 10g H2 to moles:H2=2 g/mol; 10g = 5 moles of hydrogen.Step 3: use molar ratios (coefficients) in balanced equation to determine moles of product:3/2=5/x; solve for x to get 3.3 moles of ammonia (product).Step 4: use relationship between moles and grams to get grams of product:NH3=14+1+1+1=17 g/mol. Given 3.3 moles, 17(3.3)=56.1 grams NH3.
The mass of 5 mol H2 is 10,08 g.
This element is carbon.
2,196.10-12 pmol of Na3PO4. (p is pico)
10g Al(OH)3 is 0.12821 moles. The moles of hydroxide is thus, 0.38462 moles. If you have 1.5 moles per litre HCl and they react 1:1, you need 256.4ml
10g every 29.84 seconds=Qouted by famous scientist==albert lewii=
10gI x (1 moleI / 126.9gI) = 0.079 molesI 2 significant figures.
There are one hundred 10g in 1kilo
No. of moles = mass/relitive molecular mass in this case = 10/16 = 0.625 so that's 0.625 of a mole and a mole of anything contains 6.022 x 1023 atoms = 3.76 x 1023 atoms in 10g of oxygen.
20 x 500 mg = 10g or 10g = 500mg x 20
The price depends upon the country, quality, type etc.
1.36 tablespoons of coffee has been present in 10g.
Step 1: balanced equation for the synthesis of ammonia:N2 + 3H2 --> 2NH3Step 2: convert 10g H2 to moles:H2=2 g/mol; 10g = 5 moles of hydrogen.Step 3: use molar ratios (coefficients) in balanced equation to determine moles of product:3/2=5/x; solve for x to get 3.3 moles of ammonia (product).Step 4: use relationship between moles and grams to get grams of product:NH3=14+1+1+1=17 g/mol. Given 3.3 moles, 17(3.3)=56.1 grams NH3.
The mass of 5 mol H2 is 10,08 g.