General principle of mole:
One mole of particles of any material ALWAYS contains 6.022 * 10^23 particles.
Thus no matter whether it is gold atoms or sand or raindrops or anything countable.
It is like 1 dozen equals 12 and 1 gross equals 144.
The answer is 2,358 moles gold.
4.2 X 10^24 atoms of gold / 6.022 X 10^23 atoms per mol) = 7.0 moles of gold
Using avagadro's number of 6.022 x 10 to the 23rd atoms/mole. The answer is 1.99 moles of gold
2.61 X 10^24 atoms of gold (1 mole Au/6.022 X 10^23) = 4.33 moles of gold
44 moles of atoms
Using Avogadro's number, 0.200 moles contains 1.2044 E23 atoms of metal. 75 percent of this number is equal to 9.033 E22 atoms of gold.
12,4439 kg of gold contain 63,177 moles.
4.2 X 10^24 atoms of gold / 6.022 X 10^23 atoms per mol) = 7.0 moles of gold
2.6 moles nabr3
Using avagadro's number of 6.022 x 10 to the 23rd atoms/mole. The answer is 1.99 moles of gold
2.61 X 10^24 atoms of gold (1 mole Au/6.022 X 10^23) = 4.33 moles of gold
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
1,638 moles contain 9,864266723766.10e23 atoms.
44 moles of atoms
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
This is equivalent to 1,4 moles.
20 moles
Using Avogadro's number, 0.200 moles contains 1.2044 E23 atoms of metal. 75 percent of this number is equal to 9.033 E22 atoms of gold.