0.00833 moles of CO3
0,189 moles
Number of moles = Weight (in g) / Molecular mass (in g/mol) = 8.718 / 96.09 = 0.0907 moles
2,8 moles of calcium carbonate have 240,208 g.
1,5 moles of potassium carbonate have 276,41 g.
3(2.6) = 7.8 moles of ions
0,189 moles
A 22.5 gram sample of ammonium carbonate contains 4.5 moles of ammonium ions.
As the formula for ammonium carbonate is (NH4)2CO3, there are two moles of ammonium for every mole of ammonium carbonate. Just double the given number.
There are 9 moles of NH4 (Ammonium ions) in Ammonium carbonate. There are 2 moles of NH4 per molecule and 4.5 molecules, so 2 moles times 4.5 is 9 moles.
Number of moles = Weight (in g) / Molecular mass (in g/mol) = 8.718 / 96.09 = 0.0907 moles
Ammonium carbonate = (NH4)2CO3. Its molar mass is 96g/mol. 6.965g/96 = 0.7255mol.
I suppose that the answers are: - 0,9 moles aluminium ions - 2,7 moles chloride ions
2,8 moles of calcium carbonate have 240,208 g.
There are 2.8604 moles of ammonium ions in 6.955.
1,5 moles of potassium carbonate have 276,41 g.
3(2.6) = 7.8 moles of ions
Ammonium carbonate is (NH4 )2 CO3 and the molar mass is 96.0878 so you just divide 8.790 g/96.0878 and you get 0.91478835 and since there are two ammonium (NH4 )2 ions you multiply 0.91478835 * 2 and get 0.1830 mol.