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0.00833 moles of CO3

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Q: How many moles of ions are there in 0.500g of carbonate ions?
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How many moles of ammonium ions are in 8.738 g of ammonium carbonate?

0,189 moles


How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?

A 22.5 gram sample of ammonium carbonate contains 4.5 moles of ammonium ions.


How many moles of ammonium ions are in 6.965 of ammonium carbonate?

As the formula for ammonium carbonate is (NH4)2CO3, there are two moles of ammonium for every mole of ammonium carbonate. Just double the given number.


How many moles of ammonium ions are in 4.50 mol NH4 2CO3?

There are 9 moles of NH4 (Ammonium ions) in Ammonium carbonate. There are 2 moles of NH4 per molecule and 4.5 molecules, so 2 moles times 4.5 is 9 moles.


How many moles of ammonium ions are in 8.718 g of ammonium carbonate?

Number of moles = Weight (in g) / Molecular mass (in g/mol) = 8.718 / 96.09 = 0.0907 moles


How many moles of ammonium ions are in 6.965 g of ammonium carbonate?

Ammonium carbonate = (NH4)2CO3. Its molar mass is 96g/mol. 6.965g/96 = 0.7255mol.


How many moles of ions AL3 and how many mols of ions CL-has in 0.9 mols of ALCL3?

I suppose that the answers are: - 0,9 moles aluminium ions - 2,7 moles chloride ions


How many grams are in 2.8 moles of calcium carbonate?

2,8 moles of calcium carbonate have 240,208 g.


How many moles of ammonium ions are in 6.955?

There are 2.8604 moles of ammonium ions in 6.955.


How many grams of potasium carbonate are in 1.5 moles of this substance?

1,5 moles of potassium carbonate have 276,41 g.


How many moles of ions are in 2.6 mole of K2SO4?

3(2.6) = 7.8 moles of ions


How many moles of ammonium ions are in 8.790g of ammonium carbonate?

Ammonium carbonate is (NH4 )2 CO3 and the molar mass is 96.0878 so you just divide 8.790 g/96.0878 and you get 0.91478835 and since there are two ammonium (NH4 )2 ions you multiply 0.91478835 * 2 and get 0.1830 mol.