The molecular mass of H2O is 2(1.0) + 16.0 = 18.0Amount of H2O = 3/18.0 = 0.167mol
The Avogadro's number is 6.02 x 10^23
Number of molecules of H2O in 3g sample = 0.167 x 6.02 x 10^23 = 1.00 x 10^23
To find the number of molecules in 36.0 g of H2O, you first need to convert the grams to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
Atomic mass- 1.01Formula- grams × (6.02 × 1023) / atomic mass = number of atoms1.00 grams H × (6.02 × 1023) / 1.01 grams = 5.96 × 1023 atoms of hydrogen
There are 6 molecules in the formula 3H2O: 3 molecules of water (H2O) each composed of 3 atoms (2 hydrogen and 1 oxygen).
The balanced chemical equation for the reaction is 2 C2H5OH + 3 O2 → 2 CO2 + 3 H2O. This means that two molecules of ethanol (C2H5OH) react with three molecules of oxygen (O2) to produce two molecules of carbon dioxide (CO2) and three molecules of water (H2O).
The oxidation number of H in H2O is +1, and that of O is -2. Since there are three H2O molecules, the total oxidation number would be 3(+1) + 3(-2) = -3.
To find the number of molecules in 36.0 g of H2O, you first need to convert the grams to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
Atomic mass- 1.01Formula- grams × (6.02 × 1023) / atomic mass = number of atoms1.00 grams H × (6.02 × 1023) / 1.01 grams = 5.96 × 1023 atoms of hydrogen
First write out the equation and balance it. Then look at the ratio of C8H10 to CO2 produced in the reaction (hint: use molecular weights). For example: 2A = 1B + 1C where A =4, B=5, and C=3 so, for every 8g of A you get 5g of B 20g of B will yield 20 x 5/8 = 12.5g
There are 6 molecules in the formula 3H2O: 3 molecules of water (H2O) each composed of 3 atoms (2 hydrogen and 1 oxygen).
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
The balanced chemical equation for the reaction is 2 C2H5OH + 3 O2 → 2 CO2 + 3 H2O. This means that two molecules of ethanol (C2H5OH) react with three molecules of oxygen (O2) to produce two molecules of carbon dioxide (CO2) and three molecules of water (H2O).
A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.
If we have 3 molecules of MgO and 3 molecules of H2O, this is equivalent to a total of 3 atoms of magnesium (Mg), 3 atoms of oxygen (O), and 6 atoms of hydrogen (H).
H2O consists of two Hydrogen and one Oxygen. Three sets of these would mean 9 atoms in your three molecules of water.
In 3 molecules of H2O, which is 3H2O, there are 6 hydrogen atoms and 3 oxygen atoms. You multiply the coefficient of 3 times the subscript of each element. When there is no subscript, it is assumed to be 1.
The oxidation number of H in H2O is +1, and that of O is -2. Since there are three H2O molecules, the total oxidation number would be 3(+1) + 3(-2) = -3.
First you find the Molar Mass of water using the values on the periodic table.2 Hydrogen + 1 Oxygen2*1.01 + 16.00 = 18.02 g/molThen using factor-label to cancel out units(100g H2O)*(1 mol H2O / 18.02 g H2O) = 5.54938957 molSo the number of moles in 100g of H2O is about 5.55 moles.Hope that helps.