Atomic Mass- 1.01
Formula- grams × (6.02 × 1023) / atomic mass = number of atoms
1.00 grams H × (6.02 × 1023) / 1.01 grams = 5.96 × 1023 atoms of hydrogen
100 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O)
= 3.34 X 1024 molecules of water
=========================================================
Of course you see how many oxygen atoms in that much water.
1.5 x 10^23 molecules H2O
First determine how many moles are in 4.4 g of H2O, divide 4.4 g by the molar mass of H2O, 18.015 g/mol. Divide by multiplying by the inverse of the molar mass. Then multiple the moles H2O by 6.022 x 10^23 molecules/mol.
4.4 g H2O x 1mol H2O/18.015 g H2O = 0.2442 mol H2O
0.2442 mol H2O x (6.022 x 10^23 molecules H2O)/(1mol H2O) = 1.5 x 10^23 molecules H2O
rounded to two significant figures
4 g (6.02 x 1023 atoms / 1.01 g) = 2.38 x 1024atoms
mass percent of H in H2O: 11.19%
4.9g x .1119 = 0.5483gH
0.5483gH x (1molH/1.0079gH) x (6.022E23/1molH) = 3.3E23 (3.275951x10^23)
4 moles of hydrogen contain 48,177126856.1023 atoms.
2
One molecule of H2O has 3 atoms (two hydrogens and one oxygen). So there will be 12 atoms in 4H2O.
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
The answer is: C3H8 + 5O2 3CO2 + 4H2O
C3H8 + 5O2 >> 3CO2 + 4H2O ( and, of course, energy )
how many atoms are there in magnesiumoxide 2 atoms are in magnesium 2 atoms are in magnesium
coefficiant
One molecule of H2O has 3 atoms (two hydrogens and one oxygen). So there will be 12 atoms in 4H2O.
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
The answer is: C3H8 + 5O2 3CO2 + 4H2O
2NH4NO3->2N2+O2+4H2O
Think of it like this. O = C = O There are three altogether. One carbon atom and two oxygen atoms. :D
C3H8 + 5O2 >> 3CO2 + 4H2O ( and, of course, energy )
4 molecules It's Na2CrO4 · 4H2O
Propane is burned to provide the heat in many cooking grills. The chemical reaction for this process is shown in the equation below. C3H8 + 5O2 ? 3 CO2 + 4H2O + energy What are the products in this chemical reaction? 3CO2 + 4H2O + energy
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).MM Co(C2H3O2)2: 177.02g (anhydrate)+ MM 4H2O: 72.06g (water)MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).72.06g249.08g x 100%Percent water of hydrate is 28.93%.Finding Molar Mass# atoms Element A * Atomic Mass Element A = Mass A# atoms Element B * Atomic Mass Element B = Mass B... etc.Add up all of the mass values and you have the molar mass of the substance.