0
Three different elements: C, H, O.
3 C-atoms
8 H-atoms
10 (=3*2+4) O-atoms
What else can I help you with?
How many reactions are in this equation c3h8 5o2 3co2 4h2o?
The equation you provided is not balanced. To balance it, you need to make sure that the number of each type of atom is the same on both sides of the equation. Once the equation is balanced, you can count the number of reactions by looking at the coefficients of the reactants and products in the balanced equation.
How many moles of oxygen are necessary to react completely with 4 moles of propane?
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
How many moles of oxygen are necessary to react completely with moles of propane?
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
What are the products of the complete combustion of propane?
carbon dioxide and water oxygen gas and carbon atoms
How many moles of carbon dioxide are produced when 10 moles of propane are combusted?
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
How many different elements are involved in C3H8 5O2 - 3CO2 4H2O?
C-carbon H-hydrogen O-oxygen Three different elements.
How many reactions are in this equation c3h8 5o2 3co2 4h2o?
The equation you provided is not balanced. To balance it, you need to make sure that the number of each type of atom is the same on both sides of the equation. Once the equation is balanced, you can count the number of reactions by looking at the coefficients of the reactants and products in the balanced equation.
How many grams of oxygen are required to complete combustion of 2.75 moles of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
How many moles of C3H8 are needed to react with 0.567 mol of 02?
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
Propane is burned to provide the heat in many cooking grills the chemical reaction for this process is shown in the equation below c3h8 plus 5o2 3 co2 plus 4h2o plus energy what are the products?
Propane is burned to provide the heat in many cooking grills. The chemical reaction for this process is shown in the equation below. C3H8 + 5O2 ? 3 CO2 + 4H2O + energy What are the products in this chemical reaction? 3CO2 + 4H2O + energy
How many elements are involved in c3h8 5o2 3co2 4h2o?
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
How many moles of oxygen are necessary to react completely with 4 moles of propane?
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
How many moles of oxygen are necessary to react completely with moles of propane?
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
In an experiment 1 mol of propane is burned to form carbon dioxide and water. How many moles of oxygen are needed for this reaction?
The combustion of propane (C3H8) can be represented by the balanced chemical equation: (C3H8 + 5O2 \rightarrow 3CO2 + 4H2O). According to this equation, 1 mole of propane requires 5 moles of oxygen for complete combustion. Therefore, 5 moles of oxygen are needed for the reaction when burning 1 mole of propane.
C3H8 plus 5O2---3CO2 plus 4H2O. How many moles of water form when 4.50 L propane gas C3H8 completely react?
For every mole of propane (C3H8) that reacts, 4 moles of water (H2O) are produced. Since 1 mole of gas occupies about 22.4 L at STP, if 4.50 L of propane reacts, you would need to convert the volume of propane to moles using the ideal gas law to determine the moles of water produced.
What are the products of the complete combustion of propane?
carbon dioxide and water oxygen gas and carbon atoms
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
