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Three different elements: C, H, O.
3 C-atoms
8 H-atoms
10 (=3*2+4) O-atoms
Flossie Kozey
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How many reactions are in this equation c3h8 5o2 3co2 4h2o?
The answer is: C3H8 + 5O2 3CO2 + 4H2O
How many moles of oxygen are necessary to react completely with moles of propane?
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
How many moles of carbon dioxide are produced when 10 moles of propane are combusted?
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
How many atoms in 4H20?
One molecule of H2O has 3 atoms (two hydrogens and one oxygen). So there will be 12 atoms in 4H2O.
How many reactions are in this equation c3h8 5o2 3co2 4h2o?
The answer is: C3H8 + 5O2 3CO2 + 4H2O
How many different elements are involved in C3H8 5O2 - 3CO2 4H2O?
C-carbon H-hydrogen O-oxygen Three different elements.
C3H8 plus 5O2---3CO2 plus 4H2O. How many moles of water form when 4.50 L propane gas C3H8 completely react?
5048+w4g5=23vm32
How many elements are involved in c3h8 5o2 3co2 4h2o?
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
How many grams of oxygen are required to complete combustion of 2.75 moles of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
How many moles of C3H8 are needed to react with 0.567 mol of 02?
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
Propane is burned to provide the heat in many cooking grills the chemical reaction for this process is shown in the equation below c3h8 plus 5o2 3 co2 plus 4h2o plus energy what are the products?
Propane is burned to provide the heat in many cooking grills. The chemical reaction for this process is shown in the equation below. C3H8 + 5O2 ? 3 CO2 + 4H2O + energy What are the products in this chemical reaction? 3CO2 + 4H2O + energy
How many moles of oxygen are utilized by the complete combustion of propane?
Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.
How many moles of oxygen are necessary to react completely with moles of propane?
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
How many grams of CO2 are used when 8.0g of O2 are produced?
First of all you have to determine the equation for the reaction: C3H8 + 5 O2 -----> 3CO2 + 4H2O Now we determine the limiting reactant: C3H8= (12*3) + (8*1)=44g/mol 8g C3H8 * (1mol/44g ) * (5 O2 / 1 C3H8) * (32g/1mol O2) = 29.09 g O2 So, 8g of C3H8 would use up 29.09 grams of O2 in order for this reaction to go to compleation. Since we have only 8 g of O2, O2 will run out first. So, it is considered the limiting reactant. In the next step we use the same method to determine mass of CO2 formed: 8g O2 * (1mol O2 /32g) * (3CO2 / 5 O2) * (44g/1mol CO2) = 6.6 g CO2 if you have any more questions feel free to e-mail me on micuninikola@yahoo.com I ll be glad to help out Nick Nikolic, Chemistry 121 student
If 100.0g C3H8 is burned completely how many grams CO2 would be produced if the only source of carbon is C3H8?
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
