Three different elements: C, H, O.
3 C-atoms
8 H-atoms
10 (=3*2+4) O-atoms
Combustion reactions involve reacting a substance with oxygen to form oxides of the elements that made up the substance. In the case of C3H8 this means carbon dioxide and water: C3H8 + 5 O2 ----> 3 CO2 + 4 H2O
Propane is a compound.
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
28.76 g of O2 Write the complete combustion reaction and balance C3H8 + 5O2 yields 3CO2 + 4H2O set up ratio based on molar masses (stat organized) 44g = 160g X 7.91g Solve for X I have found this method easier for students (gen. chem) as compared to dimensional analysis
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
C-carbon H-hydrogen O-oxygen Three different elements.
C3h8+ 5o2---> 3co2+ 4h2o
C3H8 + 5O2 --> 3CO2 + 4H2O
C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) is the chemical equation for the combustion of propane.
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
C3h8 + 5o2 -> 3co2 + 4h2o
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
C3h8 + 5o2 --> 3co2 + 4h2o
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
The balanced equation for the burning of propane (C3H8) is: C3H8 + 5O2 -> 3CO2 + 4H2O
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5