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How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
How many moles of nitrogen are in 2.5 10 -2 moles of quinine?
Since quinine has a nitrogen atom in its chemical formula, 1 mole of quinine contains 1 mole of nitrogen atoms. Therefore, in 2.5 x 10^-2 moles of quinine, there are also 2.5 x 10^-2 moles of nitrogen atoms.
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3?
First of all, your formula cannot be right. There is no way the formula is Al2S2O33. Sorry, not happening. Maybe it is supposed to be Al2S2O3? But you need to know the actual formula to answer this question.Step 1) Once you have the correct formula, determine the molecular weight of this compound. See the Related Questions link to the left for how to do that.Step 2) Then convert the 25.6 grams of whatever this stuff is into moles. See the Related Questions links to the left for how to convert grams into moles.Step 3) Then based on the formula (as it is now), there are 2 atoms of sulfur for every molecule of this stuff. That means however many molecules you calculated in Step 2 above, you have twice as many moles of sulfur.Step 4) Then convert from moles to atoms. To do that multiply by Avogadro's number and see the Related Questions links for how to do that!
How many atoms of sulfur in al2so43?
There are 3 atoms of sulfur in Al2(SO4)3.
How many moles of Sulfur are in 2.55g of aluminum sulfate?
To find the number of moles of sulfur in 2.55g of aluminum sulfate, you need to first calculate the molar mass of aluminum sulfate (Al2(SO4)3), which is 342.15 g/mol. Sulfur accounts for 3 moles in one mole of aluminum sulfate, so you can calculate the number of moles by dividing the given mass (2.55g) by the molar mass of aluminum sulfate.
How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
How many moles of nitrogen are in 2.5 10 -2 moles of quinine?
Since quinine has a nitrogen atom in its chemical formula, 1 mole of quinine contains 1 mole of nitrogen atoms. Therefore, in 2.5 x 10^-2 moles of quinine, there are also 2.5 x 10^-2 moles of nitrogen atoms.
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3?
First of all, your formula cannot be right. There is no way the formula is Al2S2O33. Sorry, not happening. Maybe it is supposed to be Al2S2O3? But you need to know the actual formula to answer this question.Step 1) Once you have the correct formula, determine the molecular weight of this compound. See the Related Questions link to the left for how to do that.Step 2) Then convert the 25.6 grams of whatever this stuff is into moles. See the Related Questions links to the left for how to convert grams into moles.Step 3) Then based on the formula (as it is now), there are 2 atoms of sulfur for every molecule of this stuff. That means however many molecules you calculated in Step 2 above, you have twice as many moles of sulfur.Step 4) Then convert from moles to atoms. To do that multiply by Avogadro's number and see the Related Questions links for how to do that!
How many atoms of sulfur in al2so43?
There are 3 atoms of sulfur in Al2(SO4)3.
How many moles of Sulfur are in 2.55g of aluminum sulfate?
To find the number of moles of sulfur in 2.55g of aluminum sulfate, you need to first calculate the molar mass of aluminum sulfate (Al2(SO4)3), which is 342.15 g/mol. Sulfur accounts for 3 moles in one mole of aluminum sulfate, so you can calculate the number of moles by dividing the given mass (2.55g) by the molar mass of aluminum sulfate.
How many elements are present in Al2SO4?
3 elements are present 1. Aluminum 2.Sulfur 3.oxygen the sulfur and oxygen combine to form Sulfate therefore it is called Aluminum Sulfate
How do you find out how many oxygen atoms are in 4.70 g of Al2 SO4 3?
How many moles are in 4.70g of NH3?
How many moles of Aluminum Sulfate are present when 0.12 moles of each compound is dissolved in water?
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
Which elements are in the present aluminum sulate?
Aluminum sulfate has the chemical formula Al2(SO4)3, so the elements present would be aluminum (Al), sulfur (S) and oxygen (O).
Find the atoms for AL2(SO4)3?
17 atoms To find the number of atoms in Al2(SO4)3 (Aluminum sulfate) we’ll add up the number of atoms for Al, S, and O. The small number after the element symbol is called the subscript and this tells us how many of that atom are in the compound. For example Al2 means there are two Aluminum atoms. When there is no number after an element, as is the case with Sulfur (S), we assume there to be one atom of that element. For example, in Al2(SO4)3 we have only one S atom. For AL2(SO4)3 there are a total of 17 atoms in the compound. https://www.youtube.com/watch?v=rBswe59mXeI
How many moles of aluminum are present in 856g of aluminum sample?
To determine the number of moles of aluminum present in 856g, you need to divide the mass by the molar mass of aluminum. The molar mass of aluminum is approximately 26.98 g/mol. So, 856g ÷ 26.98 g/mol ≈ 31.7 moles of aluminum are present in 856g.
