0.34 grams water (1 mole H2O/18.016 grams)
= 0.02 moles water
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95,474 moles
27.4 g H2O x 1 mole/18 g = 1.52 moles
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
For every mole of methyl alcohol (CH3OH) that is combusted, one mole of CO2 and two moles of water are produced. Therefore, if 3.25 moles of CO2 are formed, this means 3.25 moles of methyl alcohol were combusted, leading to the production of 6.5 moles of water (2 moles of water for every mole of CH3OH).
The answer is 6 moles.
9.991 Moles (water) 8.982 Moles (heavy water)
95,474 moles
180 grams of water is 10 moles of water.
3.2 moles of water (H2O)
The answer is 3 moles.
54,0 grams of water is equivalent to 3 moles.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
The answer is 6 moles.
6,00 g of water contains how 0,33 moles.
10,55 moles of water are obtained.
yes