Given the balanced equation
C10H8 + 12O2 --> 10CO2 + 4H2O
In order to find the mass in grams of CO2 that can be produced from 25.0 moles of C10H8, we must convert from moles to mass (mol --> mass conversion).
25.0 mol C10H8 * 10 molecules CO2 * 44.01g CO2 = 1.1025x104 (11025)g CO2
------------------------- 1 molecule C10H8
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
The balanced chemical equation for the reaction of C2H6O with O2 is C2H6O + 3O2 -> 2CO2 + 3H2O. This means that 1 mole of C2H6O reacts with 3 moles of O2. Therefore, to completely react with 4.0 moles of C2H6O, you would need 4.0 moles x 3 moles O2/1 mole C2H6O = 12 moles of O2.
The balanced chemical equation for the production of water from hydrazine is: 4N2H4(l) + O2(g) → 4H2O(g) + 4N2(g) From the equation, it can be seen that 4 moles of water are produced for every 1 mole of hydrazine. Therefore, if 14000 moles of hydrazine are used, 14000 moles of water will be produced.
Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
10,55 moles of water are obtained.
Sulfuric acid is not obtained from water.
6,49 moles of water are obtained.
Two moles of water are produced.
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
9
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
To determine how many moles of CH4 (methane) are produced along with 11 moles of water, we need the balanced chemical equation for the reaction. In the case of methane production from a reaction like the one involving carbon dioxide and hydrogen (CO2 + 4H2 → CH4 + 2H2O), every mole of CH4 produced yields 2 moles of water. Therefore, if you have 11 moles of water, you would produce 5.5 moles of CH4.
32 g ethanol is equivalent to 0,695 moles.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?