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Sulfuric acid is not obtained from water.

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9y ago

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How many moles of H2O are produced when 1 mole of MgOH2 reacts with 1 mole of H2SO4?

The balanced chemical equation for the reaction between magnesium hydroxide (Mg(OH)2) and sulfuric acid (H2SO4) is: Mg(OH)2 + H2SO4 -> MgSO4 + 2H2O. From the equation, 1 mole of Mg(OH)2 will produce 2 moles of water (H2O) when it reacts with 1 mole of H2SO4.


How many moles of water H2O are produced from the reaction of 16 grams methane CH4 with an unlimited supply of oxygen O2. How many grams of H2O is this?

Two moles of water are produced.


How many moles of H2O are produced when 0.721mol of octane is burned?

6,49 moles of water are obtained.


Use the following balanced equation to answer these question n2h4 plus 2h2o2--n2 plus 4h2o how many moles of h2o are produced from 1.5 moles of n2h4?

N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced


How many moles of h2o are produced when 2.55 moles of O2 react?

4


How many moles of H2O can be formed when 4.5 moles of NH3 react with 3.2 moles of O2 NH3 plus O2 yields NO plus H2O?

Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.


How many moles of H2O can be produced from 6.55 mol of C2H5OH?

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How many moles of water are in this reaction 2C8H18 25O2- 16CO2 18H2O?

There are 18 moles of water produced in the reaction. This is determined by the stoichiometry of the balanced chemical equation, which shows that for every 2 moles of C8H18 consumed, 18 moles of H2O are produced.


How many moles of H2O are present in 150.0G of H2O?

The answer is 8,33 moles.


How many moles of H2O is 7.038 grams of H2O?

The answer is 0,44 moles.


How many moles of H2O are present in 75.0g H2O?

There are 4.17 moles of H2O present in 75.0g of H2O.


How many moles of water can be produced by burning 325g of octane in excess oxygen?

Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O