Sulfuric acid is not obtained from water.
The balanced chemical equation for the reaction between magnesium hydroxide (Mg(OH)2) and sulfuric acid (H2SO4) is: Mg(OH)2 + H2SO4 -> MgSO4 + 2H2O. From the equation, 1 mole of Mg(OH)2 will produce 2 moles of water (H2O) when it reacts with 1 mole of H2SO4.
Two moles of water are produced.
6,49 moles of water are obtained.
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
4
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
If burnt with excess O2 then 19.65 (=3*6.55) mole H2O
There are 18 moles of water produced in the reaction. This is determined by the stoichiometry of the balanced chemical equation, which shows that for every 2 moles of C8H18 consumed, 18 moles of H2O are produced.
The answer is 8,33 moles.
The answer is 0,44 moles.
There are 4.17 moles of H2O present in 75.0g of H2O.
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O