Go ahead and write the balanced equation:
H2SO4 + 2NaOH --> Na2SO4 +2H2O
If you have 1 mole of the reactant H2SO4, it will yield 2 moles of the product water.
You can tell by the coefficients.
The stoichiometry of the reaction determines the amount of Mg(OH)2 produced. In this case, the balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, 6 moles of KOH are needed to completely react with it and produce 3 moles of Mg(OH)2.
Zn + H2SO4 ---> ZnSO 4 + H2 so one mole of zinc and 1 mole of sulfuric acid produces one mole of hydrogen molecules and thus two moles of hydrogen atoms. So 0.36 moles of zinc will produce 0.36 moles of hydrogen molecules and thus 0.72 moles of hydrogen atoms.
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
The balanced chemical equation for the reaction is: H2SO4 + 2NaOH -> Na2SO4 + 2H2O. To find the amount of Na2SO4 produced, first find the limiting reactant by calculating the moles of each reactant. Then, use the mole ratio from the balanced equation to determine the moles of Na2SO4 produced. Finally, convert moles to grams using the molar mass of Na2SO4 to find the final amount.
To find the concentration of H2SO4, first calculate the number of moles of NaOH using the formula: moles = concentration x volume (in dm^3). Then, use the balanced equation to determine the mole ratio between NaOH and H2SO4. Finally, calculate the concentration of H2SO4 by dividing the moles of H2SO4 by the volume of H2SO4 used.
1337
The answer is one mole.
The stoichiometry of the reaction determines the amount of Mg(OH)2 produced. In this case, the balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, 6 moles of KOH are needed to completely react with it and produce 3 moles of Mg(OH)2.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
Zn + H2SO4 ---> ZnSO 4 + H2 so one mole of zinc and 1 mole of sulfuric acid produces one mole of hydrogen molecules and thus two moles of hydrogen atoms. So 0.36 moles of zinc will produce 0.36 moles of hydrogen molecules and thus 0.72 moles of hydrogen atoms.
Sulfuric acid is not obtained from water.
1,4 moles carbon monoxide are produced.
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
The balanced chemical equation for the reaction is: H2SO4 + 2NaOH -> Na2SO4 + 2H2O. To find the amount of Na2SO4 produced, first find the limiting reactant by calculating the moles of each reactant. Then, use the mole ratio from the balanced equation to determine the moles of Na2SO4 produced. Finally, convert moles to grams using the molar mass of Na2SO4 to find the final amount.
To find the concentration of H2SO4, first calculate the number of moles of NaOH using the formula: moles = concentration x volume (in dm^3). Then, use the balanced equation to determine the mole ratio between NaOH and H2SO4. Finally, calculate the concentration of H2SO4 by dividing the moles of H2SO4 by the volume of H2SO4 used.
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.