26
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
The balanced chemical equation for the production of water from hydrazine is: 4N2H4(l) + O2(g) → 4H2O(g) + 4N2(g) From the equation, it can be seen that 4 moles of water are produced for every 1 mole of hydrazine. Therefore, if 14000 moles of hydrazine are used, 14000 moles of water will be produced.
The balanced chemical equation for the reaction of C2H6O with O2 is C2H6O + 3O2 -> 2CO2 + 3H2O. This means that 1 mole of C2H6O reacts with 3 moles of O2. Therefore, to completely react with 4.0 moles of C2H6O, you would need 4.0 moles x 3 moles O2/1 mole C2H6O = 12 moles of O2.
Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
10,55 moles of water are obtained.
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
6,49 moles of water are obtained.
Sulfuric acid is not obtained from water.
Two moles of water are produced.
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
9
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
32 g ethanol is equivalent to 0,695 moles.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
To find the mass of water produced, we first need to determine the molar ratio of water to nitrous oxide in the reaction. Once we have the mole ratio, we can use it to calculate the moles of water produced from the moles of nitrous oxide. Finally, we can convert the moles of water to grams using the molar mass of water.