Mass Number - Atomic Number = Number Of Neutrons
So for Sc:
45 -21 = 24 neutrons
However there is also an unstable Sc isotope (0.6 s half-life time) with mass number 41, so this one has 20 neutrons.
Sc is actually atomic number 21, there are 21 protons, 21 electrons, and usually 24 neutrons
Number of neutrons = Mass number - atomic number =15 - 6 = 9 neutrons are there in C-15.
The atomic number of cesium is 55. The number of neutrons is the isotope mass number minus atomic number, or in this instance 86 neutrons.
For each isotope of Rf the number of neutrons is different.Number of neutrons = Mass number of an Rf isotope - 104
Number of neutrons = mass number - atomic number = 40 - 20 = 20 neutrons
Sc is actually atomic number 21, there are 21 protons, 21 electrons, and usually 24 neutrons
21 protons, 21 electrons and 23 neutrons
The atomic number of scandium is 21. So it has 21 protons and 21 electrons. Number of neutrons depends on the isotope. Number of neutrons = Mass number - Atomic number Sc-45 isotope has 24 neutrons
number of neutrons = mass number - number of protons = 28 - 13 = 15 neutrons
The number of neutrons depends on the atom. In general, mass number = atomic number + number of neutrons.
Number of neutrons = Mass number - Atomic number = 63 - 29 = 34 neutrons
All selenium atoms have 34 protons, because that is what defines Selenium. The number that comes after an isotope name is the mass number, which is the sum of the protons and neutrons. Because we know the sum of the protons and neutrons, and the number of protons, we can easily deduce the number of neutrons.p=# of protons n=# of neutrons, and mn=mass numberp+n=mnn=mn-pn=(76)-(34)n=42
How many neutrons would it have if it had 11 neutrons? 11.
Number of neutrons = Mass number - Atomic number = 37 - 17 = 20 neutrons
For each isotope the number of neutrons is different. Number of neutrons = Mass number of an Tc isotope - 43
Mass number = Atomic number (or number of protons) + Number of neutrons
The symbol is Ba. The number of neutrons equal the number of protons.