One molecule of C6H12O6 has 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
Glucose is C6H12O6. So there are 6 carbons (C), 12 hydrogens (H) and 6 oxygens (O).
The atomic number of an element tells you how many protons an atom of that element contains. This number is unique to each element and is found on the periodic table. The number of protons in an atom determines the element's identity.
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
The chemical formula shows you this. The subscripted number next to each element shows how many atoms are present in a molecule or formula unit. If no number is shown, then only one atom of that element is present.
There are 6 atoms of oxygen in a molecule of glucose (C6H12O6).
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Glucose (C6H12O6) has 6 carbon atoms, 12 hydrogen atoms, 6 oxygen atoms.
The answer depends on how many atoms of X and Z are found in each molecule of the compound.
Glucose is C6H12O6. So there are 6 carbons (C), 12 hydrogens (H) and 6 oxygens (O).
C6H12O6. Six carbon atoms, 12 hydrogen atoms and six oxygen atoms.
Helium has 2 valence electrons.
Technically no, molecular formula tells you how many atoms of each element compose a molecule. For example O: oxygen C: Carbon H: hydrogen Carbon dioxides molecular formula is CO2 Atmospheric oxygen is O2 Glucose's molecular formula is C6H12O6
The atomic number of an element tells you how many protons an atom of that element contains. This number is unique to each element and is found on the periodic table. The number of protons in an atom determines the element's identity.
The subscript on an element indicates how many atoms of the element are present: ex: O2 - the 2 shows there are two oxygen's present C6H12O6(sugar)- there are 6 carbon 12 hydrogen and 6 oxygen
The subscript on an element indicates how many atoms of the element are present: ex: O2 - the 2 shows there are two oxygen's present C6H12O6(sugar)- there are 6 carbon 12 hydrogen and 6 oxygen
There are 88.
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.