It outermost electron in Krypton is 4s1 so the quantum number set is:
n l ml ms
4 0 0 1/2
n= principal quantum number
l- angular shapes of the lob
ml- orientation of the lobe
ms- magnetic spin of the lobe , which always alternates between the values 1/2 and -1/2
Note that the quantum number l is always zero for the s orbital because there are only one subshell.
Nitrogen has 5 electrons in its outer shell, and Bromine has 7 electrons in its outer shell.
Boron has three electrons in its outer shell
Na, Rb, Al3+, and S2- do not have a noble gas configuration as they do not have the complete outer shell of electrons like a noble gas. O2, Br, Ca, and O2- have noble gas configurations as they either have a complete outer shell of electrons or have gained/lost electrons to achieve a stable noble gas configuration.
There are 7 electrons! Hehe
Nitrogen has five electrons in its outer shell and bromine has seven in its outer shell.
Rubidium (Rb) has a +1 ion, will have the same electron configuration as krypton (Kr) because the +1 status means it has lost an electron. The configuration is written 1s22s22p63s23p64s23d104p6.
paramagnetic
1 -apex
Nitrogen has 5 electrons in its outer shell, and Bromine has 7 electrons in its outer shell.
Boron has three electrons in its outer shell
Vanadium has on the outer shell two electrons.
7Fluorine has 7 electrons in the outer level.
Calcium has two electrons in the outer shell.
Na, Rb, Al3+, and S2- do not have a noble gas configuration as they do not have the complete outer shell of electrons like a noble gas. O2, Br, Ca, and O2- have noble gas configurations as they either have a complete outer shell of electrons or have gained/lost electrons to achieve a stable noble gas configuration.
There are 7 electrons! Hehe
Two electrons
There are three electrons in boron's outer energy level.