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The oxidation number of manganese depends on the particular compound in which manganese is present. The most common oxidation states are +2 as in MnCl2, + 4 as in MnO2, and + 7 as in potassium permanganate, KMnO4.

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13y ago
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11y ago

-2 for each O

+2 for Mn

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11y ago

+1 for each H, -2 for each O, +6 for Mn

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Q: How many oxidation numbers are in MnO2?
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Related questions

Rank these items in order of increasing oxidation number for manganese Mn KMnO4 MnO2?

MnO2: oxidation number +4KMnO4: oxidation number +7


What is the oxidation number of MN in 2MnO4-?

I assume you mean the oxidation number of Mn in the permanganate ion , MnO4- The sum of the oxidation numbers is the charge on a polyatomic ion so Mn has an oxidation number of +7 as each O is assigned -2.


What is oxidation number of MnO2?

-2 for each O, +4 for Mn


What is the oxidation number of MnO2?

O2 is -2 so Mn is +4


What is the oxidation number for Mn in the formula H2MnO3?

MnO2 manganese(IV) oxide. Oxygen has a -2 oxidation state (oxidation state is a better term here as oxidation number is better used for complexes- they give the same answer for this compound)


What is the change of oxidation number of manganese when MnO2 becomes Mn2O3?

The change is from 4 to 3.


Rank these items in order of increasing oxidation number for manganese MnCl2 Mn KMnO4 Mno2 lowest oxidation number?

MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7


Give you five substances that undergoes oxidation reaction?

Carbon, Sulfur, CO, FeCl2, MnO2..


What is magnanese IV oxide?

The chemical formula of this is MnO2.It is brown in colour. The oxidation number of Mn is 4 in this compound.


What is the oxidation numbers in PO34?

The oxidation numbers in PO43- , phosphorus oxidation number=+5; oxygen = -2


What is the sum of the oxidation numbers for P2O5?

There are two oxidation numbers. P shows +5 oxidation number.


Why must oxidation numbers be assigned to the elements before writing a chemical formula?

The oxidation numbers of the elements in a chemical formula, some of which will be positive and others of which will be negative, when multiplied by the numbers of atoms with each oxidation number, must produce products that add to a net result of zero.