6.022 X 10^23 atoms of O2
this is one mole of anything.
To calculate the percentage of oxygen in carbon dioxide, you can use the molecular formula of carbon dioxide (CO2), which consists of one carbon atom and two oxygen atoms. The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon and 2 * 16.00 g/mol for oxygen). To find the percentage of oxygen in CO2, divide the molar mass contribution of oxygen (32.00 g/mol) by the molar mass of CO2 (44.01 g/mol) and multiply by 100. The percentage of oxygen in carbon dioxide is approximately 72.7%.
To find the grams in 0.644 mol of oxygen, you need to multiply the number of moles by the molar mass of oxygen. The molar mass of oxygen is approximately 16 g/mol. Therefore, 0.644 mol of oxygen would contain 0.644 mol x 16 g/mol = 10.304 grams of oxygen.
The molar mass of MgO is 40.3 g/mol (Mg: 24.3 g/mol, O: 16 g/mol). The molar mass contribution of oxygen in MgO is 16 g/mol. Therefore, the percent composition of oxygen in MgO is (16 g/mol / 40.3 g/mol) * 100 = 39.7%.
There are 4.5 g of water, which is composed of 2 hydrogen atoms and 1 oxygen atom. The molecular weight of water is approximately 18 g/mol, so there would be approximately 0.25 mol of water in 4.5 g. Since each molecule of water has 1 oxygen atom, there are approximately 0.25 mol of oxygen atoms in 4.5 g of water, which is about 1.5 x 10^22 atoms of oxygen.
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
Average atomic mass of Ca = 40.1 Average atomic mass of O = 16.0 Mr(Ca)/Mr(O) = 40.1/16.0 = 2.51 Thus the calcium atom is about 2.5 times heavier than the oxygen atom.
To calculate the percentage of oxygen in carbon dioxide, you can use the molecular formula of carbon dioxide (CO2), which consists of one carbon atom and two oxygen atoms. The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon and 2 * 16.00 g/mol for oxygen). To find the percentage of oxygen in CO2, divide the molar mass contribution of oxygen (32.00 g/mol) by the molar mass of CO2 (44.01 g/mol) and multiply by 100. The percentage of oxygen in carbon dioxide is approximately 72.7%.
Water has two hydrogen atoms, and one oxygen atom. Look up their atomic weights, add them all up, and you will get the number of grams per mol.
To calculate the theoretical mass percentage of oxygen in potassium chlorate, you would use the formula weight of oxygen divided by the formula weight of the compound (potassium chlorate) multiplied by 100. The formula weight of oxygen is 16.00 g/mol and the formula weight of potassium chlorate (KClO3) is 122.55 g/mol. So, (16.00 g/mol / 122.55 g/mol) * 100 = 13.06%.
To find the grams in 0.644 mol of oxygen, you need to multiply the number of moles by the molar mass of oxygen. The molar mass of oxygen is approximately 16 g/mol. Therefore, 0.644 mol of oxygen would contain 0.644 mol x 16 g/mol = 10.304 grams of oxygen.
The molar mass of MgO is 40.3 g/mol (Mg: 24.3 g/mol, O: 16 g/mol). The molar mass contribution of oxygen in MgO is 16 g/mol. Therefore, the percent composition of oxygen in MgO is (16 g/mol / 40.3 g/mol) * 100 = 39.7%.
moles = mass/molar mass The molar mass of an oxygen atom = 16 g mol-1, as there are two oxygen atoms in diatomic oxygen this has to be doubled. 42g / 32g mol-1 = 1.3125 moles
There are 4.5 g of water, which is composed of 2 hydrogen atoms and 1 oxygen atom. The molecular weight of water is approximately 18 g/mol, so there would be approximately 0.25 mol of water in 4.5 g. Since each molecule of water has 1 oxygen atom, there are approximately 0.25 mol of oxygen atoms in 4.5 g of water, which is about 1.5 x 10^22 atoms of oxygen.
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
The molar mass of oxygen in phenylalanine is 16.00 g/mol. To calculate the mass percent of oxygen in phenylalanine, divide the molar mass of oxygen by the molar mass of phenylalanine, then multiply by 100. (16.00 g/mol / 165.19 g/mol) * 100 = 9.68% Therefore, the mass percent of oxygen in phenylalanine is approximately 9.68%.
To calculate the percent by mass of oxygen in Cr(NO3)3, we need to consider the molar mass of each element. Cr(NO3)3 consists of one chromium atom, three nitrogen atoms, and nine oxygen atoms. The molar mass of Cr(NO3)3 is 274.06 g/mol. The molar mass of just the oxygen atoms in Cr(NO3)3 is 144.00 g/mol. Therefore, the percent by mass of oxygen in Cr(NO3)3 can be calculated as (144.00 g/mol / 274.06 g/mol) x 100%.
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.