4 moles of oxygen atoms are present in 4 moles of H2O
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
To find the total moles of KNO3 needed, use the formula: moles = molarity x volume (in liters). So, moles = 2.0 mol/L x 1.5 L = 3.0 moles of KNO3. Therefore, 3.0 moles of KNO3 need to be dissolved in water to make 1.5 liters of a 2.0 M solution.
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
The combustion reaction of petrol is commonly 2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O. So for every two moles of petrol, 25 moles of oxygen are required. Thus for the 6.15 moles of gas, 153.75 moles of O2 are needed or 3440 liters.
3 moles of O, so that must be 6 moles of O2
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
Water does not need to react with oxygen to make water!
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
The amount of water formed from a reactionof hydrogen and oxygen conforms to the chemical equation: 2H2 + O2 --> 2H2O For every two moles of hydrogen which reacts with one mole of oxygen, 2 moles of water are formed.
There is no atmosphere on the moon and no water.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
To find the total moles of KNO3 needed, use the formula: moles = molarity x volume (in liters). So, moles = 2.0 mol/L x 1.5 L = 3.0 moles of KNO3. Therefore, 3.0 moles of KNO3 need to be dissolved in water to make 1.5 liters of a 2.0 M solution.
3.2 moles of water (H2O)
carbondioxide+sunlight+water=oxygen+glucose
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
carbondioxide+sunlight+water=oxygen+glucose