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How many oxygen molecules are in 22.4 liters of oxygen gas at 273 K and 101.3 kPa?
Wiki User
∙ 12y ago
Use the Ideal Gas law. See the Related Questions to the left for step-by-step instructions on how to solve the problem.
Wiki User
∙ 16y ago
Wiki User
∙ 15y agoUse the formula PV = nRT.
(101.3 kPa)(22.4 L) = (n)(8.31 (kPa L)/(mol K))(273 K)
n = ((101.3 kPa)(22.4 L)) / ((8.31 (kPa L)/(mol K))(273 K)
= 1.0 mol
Wiki User
∙ 12y agoONE mole of any gas, also oxygen, has a volume of 22.4 L at St.T&P
Wiki User
∙ 11y agoThe number of Avogadro: 6,02214129(27)×1023 molecules.
Wiki User
∙ 7y agoThe answer is approx. 0,89 moles.
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