There are approximately 4.81 x 10^24 particles in 8.00 mol. This is calculated by multiplying Avogadro's number (6.022 x 10^23 particles/mol) by the number of moles given (8.00 mol).
There are 1.08 x 10^24 particles in 1.80 mol of sulfur dioxide gas. You can determine this by multiplying Avogadro's number (6.022 x 10^23) by the number of moles.
To calculate the number of particles in 7.8g of NaCl, you first need to determine the number of moles using the molar mass of NaCl (58.44 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 particles/mol) to find the number of particles.
Number of particles = number of mol x avogadro constant = 1 x 6.02 x 1023
There are 3.00 x 6.02 x 10^23 = 1.81 x 10^24 representative particles in 3.00 mol of Sn.
1 mEq=1 mmol/valence e.g.For sodium, 1 mEq=1mmol/1 (valence of sodium=1) means, 1 mmol sodium=1 mEq of sodium take for calcium,valence=2 1 1 mEq of calcium=1mmol/2=0.5 mmol of calcium
whats the difference between mass and weight
Number of particles=number of moles x avogadro constant = 25.9 x 6.02 x 1023
There are 1.08 x 10^24 particles in 1.80 mol of sulfur dioxide gas. You can determine this by multiplying Avogadro's number (6.022 x 10^23) by the number of moles.
One mol of a pure substance contains 6.0221367 x 10^23 particles according to Avogadro's number.
To calculate the number of particles in 7.8g of NaCl, you first need to determine the number of moles using the molar mass of NaCl (58.44 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 particles/mol) to find the number of particles.
That is called Avogadro's number. It is the number of particles in a mol.
(desired moles)(6.02x1023part/1 mol)=answer
Mass of 1 liter ethanol = 800 gram Molar Mass of ethanol = 46.07 gram/mol Therefore, Number of moles in 1 liter ethanol = 800/46.07 = 17.365 mol Number of molecules in 1 mol of ethanol = 6.023 × 10²³ molecules Therefore, Number of molecules in 1 liter of ethanol = 17.365 × 6.023 × 10²³ molecules = 104.599 × 10²³ molecules = 1.05 × 10²⁵ molecules
Number of particles = number of mol x avogadro constant = 1 x 6.02 x 1023
There are 3.00 x 6.02 x 10^23 = 1.81 x 10^24 representative particles in 3.00 mol of Sn.
4.51 g x 1 mol x 6.022 x 1023 molecules = 9.95 x 1021 molecules .............273 g ............... 1 mol
1 mEq=1 mmol/valence e.g.For sodium, 1 mEq=1mmol/1 (valence of sodium=1) means, 1 mmol sodium=1 mEq of sodium take for calcium,valence=2 1 1 mEq of calcium=1mmol/2=0.5 mmol of calcium