answersLogoWhite

0

The molecular formula of ibuprofen is C₁₃H₁₈O₂. To calculate the total number of atoms, add the number of carbon, hydrogen, and oxygen atoms: 13 carbon atoms + 18 hydrogen atoms + 2 oxygen atoms = 33 atoms in ibuprofen.

User Avatar

AnswerBot

1y ago

What else can I help you with?

Related Questions

How many number of nitrogen Atoms does Ibuprofen has?

The chemical formula of ibuprofen isC13H18O2 and there are no nitrogen atoms in it.


How many moles of ibuprofen contain 7.4x1025 atoms of Carbon?

To determine the number of moles of ibuprofen containing 7.4x10^25 atoms of Carbon, we first find the number of moles present in 1 mole of ibuprofen. Ibuprofen's molecular formula is C13H18O2, so 1 mole of ibuprofen contains 13 moles of Carbon atoms. To find the moles of ibuprofen containing 7.4x10^25 Carbon atoms, we divide 7.4x10^25 by 13.


How many total atoms of oxygen are found in 6 CO2?

12


How many atoms of carbon are in 500mg of Ibuprofen?

C13H18O2 500 mg ibuprofen (1 gram/1000 mg)(1 mole ibuprofen/206.274 grams)(13 mole C/1 mole ibuprofen)(6.022 X 10^23/1 mole C) = 1.90 X 10^22 atoms of carbon in that mass ibuprofen


How many H atoms are in 0.100 mole ibuprofen?

1.08x10^24 atoms of H = wrong right answer 0.100 mole ibuprofen x 18 mole H / 1 mole ibuprofen x 6.02X10^23 / 1 mole ibuprofen = put that in your calculator and it will give u the answer


How many atoms are found in dichromate?

A dichromate ion (Cr2O7^2-) contains a total of 9 atoms - 2 chromium (Cr) atoms and 7 oxygen (O) atoms.


How many atoms are found in 4co2?

There are 3 atoms in one CO2. So there will be 12 atoms in 4CO2.


How many protons total would be found in 6 atoms of nitrogen?

Exactly 42 (7 protons per Nitrogen atom times 6 atoms).


How many atoms are in c7h5o6?

18 atoms in total.


how many atoms are there in C6H12O6?

24 atoms in total


How many atoms of elements are found in ammonia?

There are four atoms. It contains N and H atoms.


How many total atoms are in Na2H3IO?

The number of atoms is seven.