Firstly the molecule of P2O3 is actually P4O6.
Phosphorus has 5 valence electrons, oxygen has 6. So the answer is 56 for P4O6, and 28 for the stoicihiometric formua P2O3.
There are two lone pairs of electrons on the oxygen atom in the Lewis structure of CH3OH.
Iodine has 7 valance electrons
There are 18 valence electrons represented in the Lewis electron-dot structure for SO2.
H2CO. The oxygen will have two pairs of non-bonding electrons
Four valence electrons need to be accommodated in the Lewis structure for F2. Each fluorine atom contributes seven valence electrons, totaling to fourteen valence electrons in the molecule.
2 valance electrons
There are 27 valance electrons.
There are two lone pairs of electrons on the oxygen atom in the Lewis structure of CH3OH.
Iodine has 7 valance electrons
There are 18 valence electrons represented in the Lewis electron-dot structure for SO2.
H2CO. The oxygen will have two pairs of non-bonding electrons
5 electrons where two electrons are paired and three are unpaired
The hexafluorosilicate ion, SiF6^2-, has a total of 48 valence electrons available for constructing its Lewis structure.
They have different numbers of valance electrons
6 valence electrons
6 valence electrons
In the Lewis structure of SO2, there should be 18 valence electrons - 6 from sulfur and 6 from each oxygen atom.