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Do sodium salicylate react with HCl and NaOH and NaHCO3?
Sodium hydroxide in a pure form is a solid, so you cannot dissolve anything in it. Normally, NaOH is used as an aqueous solution. But salicylic acid dissolves in water, so the presence of NaOH in the water is irrelevant to the solubility of salicylic acid. It is the water, not the NaOH, that dissolves the salicylic acid.
Equation for the saponification of methyl salicylate?
C6H4(HO)COOCH3i know that's the chemical formula.sorry if this doesn't help.it is actually C7H6O3 (salicylic acid) + CH3OH (methanol) --> C8H8O3(methy salicylate) + H2O
Can you use indicator other than phenolphthalein in the titration of NaOH?
Yes, you can use indicators such as bromothymol blue or methyl orange in the titration of NaOH. These indicators change color at different pH ranges and can be used based on the specific pH endpoint needed for the titration.
How many grams of phosphoric acid are required to react with 25.4 g of sodium hydroxide?
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
What volume of 0.270 M H2SO4 is needed to react with 46.0mL of 0.100M NaOH the equation is h2so4 2naoh to na2so4 2h2oask us anything?
To find the volume of 0.270 M H2SO4 needed to react with 46.0 mL of 0.100 M NaOH, you need to use the stoichiometry of the balanced equation. The balanced equation tells you that 1 mole of H2SO4 reacts with 2 moles of NaOH. From this information, you can set up a ratio using the concentrations and volumes of the two solutions to calculate the volume of 0.270 M H2SO4 needed.
Do sodium salicylate react with HCl and NaOH and NaHCO3?
Sodium hydroxide in a pure form is a solid, so you cannot dissolve anything in it. Normally, NaOH is used as an aqueous solution. But salicylic acid dissolves in water, so the presence of NaOH in the water is irrelevant to the solubility of salicylic acid. It is the water, not the NaOH, that dissolves the salicylic acid.
Reaction between methyl salicylate and sodium hydroxide?
When methyl salicylate (oil of wintergreen) reacts with sodium hydroxide (NaOH), it undergoes saponification to form sodium salicylate and methanol. This reaction is a base-catalyzed ester hydrolysis reaction that converts the ester functional group of methyl salicylate into a carboxylate salt.
Equation for the saponification of methyl salicylate?
C6H4(HO)COOCH3i know that's the chemical formula.sorry if this doesn't help.it is actually C7H6O3 (salicylic acid) + CH3OH (methanol) --> C8H8O3(methy salicylate) + H2O
Can you use indicator other than phenolphthalein in the titration of NaOH?
Yes, you can use indicators such as bromothymol blue or methyl orange in the titration of NaOH. These indicators change color at different pH ranges and can be used based on the specific pH endpoint needed for the titration.
What is the solution of NaOH in methyl orange indicator?
The solution of NaOH in methyl orange indicator will turn from yellow to red. Methyl orange is an acid-base indicator that changes color in response to a change in pH. In the presence of a strong base like NaOH, the indicator will change to a red color indicating the basic nature of the solution.
How many grams of phosphoric acid are required to react with 25.4 g of sodium hydroxide?
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
What is the product and balanced equation of C8H5O4K NaOH?
The reaction between C8H5O4K and NaOH will produce potassium salicylate (C7H5KO3) and water. The balanced equation is: C8H5O4K + NaOH → C7H5KO3 + H2O.
What is the name of this compound---HCOOCH3----and the functional group present in it this compound reacts only with Na and not with any other forms of sodium compounds?
The compound is called methyl formate. The functional group present in it is the ester group (-COO-). Methyl formate reacts specifically with elemental sodium (Na) to form sodium formate and hydrogen gas.
How many milliliters of 0.305M NaOH would be required to titrate a 5.00mL solution of 0.616M HBr?
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
What volume of 0.270 M H2SO4 is needed to react with 46.0mL of 0.100M NaOH the equation is h2so4 2naoh to na2so4 2h2oask us anything?
To find the volume of 0.270 M H2SO4 needed to react with 46.0 mL of 0.100 M NaOH, you need to use the stoichiometry of the balanced equation. The balanced equation tells you that 1 mole of H2SO4 reacts with 2 moles of NaOH. From this information, you can set up a ratio using the concentrations and volumes of the two solutions to calculate the volume of 0.270 M H2SO4 needed.
What is the equation for the reaction of salicylic acid and sodium hydroxide?
The reaction equation for the reaction of salicylic acid (C7H6O3) with sodium hydroxide (NaOH) is: C7H6O3 + NaOH → NaC7H5O3 + H2O Overall, this reaction results in the formation of sodium salicylate and water.
Why alcohols do not react with NaOH?
Alcohols do not typically react with NaOH (sodium hydroxide) because alcohols are weak acids and NaOH is a strong base. The reaction between alcohols and NaOH would result in deprotonation of the alcohol, forming an alkoxide ion. However, this reaction is generally slow and inefficient due to the weak acidic nature of alcohols. Additionally, alcohols are poor nucleophiles, further hindering their reactivity with NaOH.
