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How much CaCl2 is needed to make 200 gal of a 35 percent solution of CaCl2 in a 200 gal tank?
Depends on how you measure your 35% - 35% w/w or 35% w/v.
Also whether you are measuring US gal or Imperial Gal. And what form of calcium chloride you are starting with (fused anhydrous or dihydrate are the two common ones)
Easier to work in litres -
200 gal imperial is about 900 litres.
Density of 35%w/w is around 1.357 @ 25°C so 1 litre of finished 35% w/w CaCl2 solution weighs 1.357 kg.
900 lt of 35%w/w weighs 900 * 1.357 = 1221kg
amount of CaCl2 (anhydrous - 100%) required = 1221 * .35 kg
= 428 kg
What else can I help you with?
What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
How many grams of calcium chloride are needed to make a 0.01 M solution?
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
How do you create CaCl2 and H2O?
To make CaCl2 and H2O, simply mix calcium chloride (CaCl2) with water (H2O). The calcium chloride will dissolve in the water, forming a solution of CaCl2 and H2O. The chemical equation for this process is: CaCl2 + H2O → CaCl2 · H2O.
What does CaCl2 plus MgSO4 make?
When CaCl2 and MgSO4 are mixed, they will not form a new compound. Instead, they will remain as two separate compounds in the solution.
How would you make 1 liter of a 1 molar solution of CaCl2?
To make 1 liter of a 1 molar solution of CaCl2, you would need to dissolve 147.02 grams of CaCl2 in enough water to make a final volume of 1 liter. This formula weight comes from the atomic weights of calcium (40.08 g/mol) and chlorine (35.45 g/mol).
What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?
144liters
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 5?
50liters
How many grams of calcium chloride are needed to make a 0.01 M solution?
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated. How much of the first 60 percent is needed to make a 100 L solution that's 50 percent?
50
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
How do you create CaCl2 and H2O?
To make CaCl2 and H2O, simply mix calcium chloride (CaCl2) with water (H2O). The calcium chloride will dissolve in the water, forming a solution of CaCl2 and H2O. The chemical equation for this process is: CaCl2 + H2O → CaCl2 · H2O.
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
What does CaCl2 plus MgSO4 make?
When CaCl2 and MgSO4 are mixed, they will not form a new compound. Instead, they will remain as two separate compounds in the solution.
How would you make 1 liter of a 1 molar solution of CaCl2?
To make 1 liter of a 1 molar solution of CaCl2, you would need to dissolve 147.02 grams of CaCl2 in enough water to make a final volume of 1 liter. This formula weight comes from the atomic weights of calcium (40.08 g/mol) and chlorine (35.45 g/mol).
How much of a 30 percent sodium chloride stock solution is needed to make 10 ml of a normal saline solution?
The volume is 0,3 mL.
