Toluene had heat of vaporization of 38.06 kJ/mol
Toluene molecular mass is 92.14 g/mol
You just need to convert heat of vaporization into kJ/g basis and multiply your 5 gram to get the required amount of heat.
To determine the number of moles in 7.51 grams of toluene, you first need to find the molar mass of toluene, which is 92.14 g/mol. Next, you divide the given mass by the molar mass to find the number of moles. Therefore, 7.51 grams of toluene is equal to 0.0815 moles.
The density of solid tungsten (near room temperature) is 19.25 g·mL−1.
I guess if you can't accurately measure 200 mgs for your 1 L solution you could just serial dilute something slightly heavier, say 2 g in 100 mL, take 10 mL of that, dilute with with 990 mL of solvent etc.
The molar mass of benzene (C6H6) is 78.11 grams per mole. The molar mass of toluene is 92.14 grams per mole. Mole fraction of a solute equals moles of solute divided by the moles of solute plus the moles of solvent. .5 of each is the mole fraction.
If you evaporate 10 grams of salt in 50 ml of water, all of the salt will remain once the water has completely evaporated. Evaporation only removes the water, leaving behind the salt.
To determine the number of moles in 7.51 grams of toluene, you first need to find the molar mass of toluene, which is 92.14 g/mol. Next, you divide the given mass by the molar mass to find the number of moles. Therefore, 7.51 grams of toluene is equal to 0.0815 moles.
The density of solid tungsten (near room temperature) is 19.25 g·mL−1.
If the fluid ounce in US is 29,573 529 562 5 mL and the density of toluene at20 0 is 0,87 g/mL, the mass is 25,73 g.
1 kilogram = 1000 grams. You now have all the information required to work out, for yourself, the answer to this and similar questions. And whether that is chicken or not makes no difference.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
I guess if you can't accurately measure 200 mgs for your 1 L solution you could just serial dilute something slightly heavier, say 2 g in 100 mL, take 10 mL of that, dilute with with 990 mL of solvent etc.
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
The energy needed to change ice into water is called the heat of fusion. For ice, this value is around 334 joules per gram. So, for 3 grams of ice, the energy gained when it changes to water would be around 1002 joules (334 joules/gram * 3 grams).
The molar mass of benzene (C6H6) is 78.11 grams per mole. The molar mass of toluene is 92.14 grams per mole. Mole fraction of a solute equals moles of solute divided by the moles of solute plus the moles of solvent. .5 of each is the mole fraction.
The change in temperature is 21 degrees Celsius. To calculate the energy required, we use the formula: Energy = mass * specific heat * change in temperature. Plugging in the values, Energy = 1.3g * 0.131 J/g°C * 21°C = 35.247 Joules. Therefore, 35.247 Joules of energy is required to heat 1.3 grams of gold from 25°C to 46°C.
To calculate the energy required to melt ice, we use the formula ( Q = m \cdot L_f ), where ( Q ) is the heat energy, ( m ) is the mass of the ice, and ( L_f ) is the latent heat of fusion for ice, approximately 334 joules per gram. For 46.0 grams of ice, the energy required would be ( Q = 46.0 , \text{g} \times 334 , \text{J/g} ), which equals about 15,364 joules. Therefore, approximately 15,364 joules are necessary to melt 46.0 grams of ice.
To prepare the phenoxide, dissolve 23.5 grams of Csl-IsOl-I in 875 milliliters of toluene. On a separate dish, dissolve 10 grams of NaOH in 150 milliliters of methyl alcohol. Pour the solution into a flask and mix.