1 kilogram = 1000 grams. You now have all the information required to work out, for yourself, the answer to this and similar questions.
And whether that is chicken or not makes no difference.
100g of rice provides about 130-150 calories, which is equivalent to approximately 500-600 kJ of energy. The exact energy content can vary based on the type of rice and cooking methods used.
One gram of protein contains about 4 kilojoules (kJ) of energy.
There are two possible answers to this question - depending on how you read it: If 2.5 kJ is converted to work but that only represents 8.5% efficiency, then the heat transferred to the surroundings will be 2.5(1-0.85)/0.85 = 26.9 kJ On the other hand, if 2.5 kJ is the total energy coming in and only 8.5% of it is converted to work, then the other 91.5% is lost to the surroundings: 2.5(1-0.085) = 2.2875 kJ
3.0 x10 1 kj A system gives off 196 kJ of heat to the surroundings and the surroundings do 4.20 x 10³ kJ of work on the system. What is the change in internal energy of the system? --- 224 kj
When 3.00 kg of ethanol is burned, approximately 107,000 kJ of heat energy is released. This calculation is based on the energy content of ethanol, which is approximately 29 kJ/g when burned.
per 100g, 1480 kj
100g of rice provides about 130-150 calories, which is equivalent to approximately 500-600 kJ of energy. The exact energy content can vary based on the type of rice and cooking methods used.
371Kj per 100 grams
kj (kilojoule) is simply a unit to measure energy.
Approximately 2080 calories. one calorie = 4.184 KJ of energy
Heat of vaporization at 100 degrees C is 40.65 kJ/mol. 100g water * 1mol/18.015g = 5.55 mol 40.65*5.55 = 225.6452956 = 226 kJ if three sig figs.
One gram of protein contains about 4 kilojoules (kJ) of energy.
A 5 ml teaspoon (4 g) of sugar contains 68 kilojoules (kJ).
60 grams of dry pasta will cookout to weigh about 100 grams
The heat of vaporization for ethane is approximately 16.7 kJ/g. Therefore, to vaporize 5 g of ethane, the energy required would be: 16.7 kJ/g * 5 g = 83.5 kJ.
Energy.
The standard enthalpy of formation of HBr(g) is -36.2 kJ/mol. For 2 moles of HBr(g), the total energy associated with its formation would be 2 * -36.2 kJ/mol = -72.4 kJ.