Heat of vaporization at 100 degrees C is 40.65 kJ/mol.
100g water * 1mol/18.015g = 5.55 mol
40.65*5.55 = 225.6452956 = 226 kJ if three sig figs.
Burning 100g of water at 100 degrees would release more energy than burning 100g of steam at 100 degrees, as water at a higher temperature has more thermal energy to be released. Burning water at 100 degrees would first need to raise its temperature to its boiling point before converting it into steam.
This would be considered a saturated solution if all 25g of KCl are completely dissolved in the 100g of water at 30 degrees Celsius.
7
6.276 kJ
6.276 kJ
A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.
100g of water is equal to 100g of ice in terms of weight, since they both have the same mass. However, the volume of the ice may be slightly larger due to the lower density of ice compared to water.
(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.
This question is misguided. I presume you mean how many spatula fulls of salt will dissolve in water. This is impossible to answer as it depends upon the mass of water, its temperature and the size of the spatula, and it's impossible to be completely consistent with what piles on the spatula. At 25 degrees C, 35.96 g of salt will dissolve in 100g of water.
Approximately 34 grams of KCl can dissolve in 100g of water at 30°C.
No, it is not.
The solubility of sodium nitrate in water at 30 degrees Celsius is approximately 180g per 100g of water. Therefore, in 250g of water, approximately 450g of sodium nitrate can dissolve.