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How much energy would be required to raise one liter of water by one degree celsius?
280,000 gallons * 16 pounds per gallon = 4,480,000 pounds of water
1 BTU to raise 1 pound of water 1 degree F (at 60 to 61, Standard Atmospheric Pressure)
1 pound of propane ~ 22,000 BTU
4,480,000 / 22,000 ~ 203
203 pounds of propane ~ 50 gallons
Burning approx 50 gallons of propane will heat 280,000 gallons of water by one degree. (Hardly a geothermal event, they burn more propane in the average tailgate at a NFL game.)
What else can I help you with?
How much KCl will remain undissolved if 500 grams is mixed in a liter of pure water at 40 degree celsius?
At 40 degrees Celsius, the solubility of KCl in water is approximately 34 grams per 100 grams of water. Therefore, in a liter of pure water at 40 degrees Celsius, 340 grams of KCl can dissolve. If 500 grams of KCl is added, 160 grams will remain undissolved since 500 grams - 340 grams = 160 grams.
What is the density of oxygen at 25 degrees Celsius?
The density of oxygen at 25 degrees Celsius is approximately 1.1839 grams per liter (g/L).
How much energy does it take to make ethanol fuel?
The energy required to produce ethanol fuel varies depending on the production process, but it typically takes about 0.25-0.3 kWh of energy to produce one liter of ethanol. This includes energy inputs for growing and harvesting the feedstock, processing it into ethanol, and distilling the ethanol.
What is the solubility of urea in water at 25 degrees Celsius?
the solubility of urea solution at 20 degrees celsius is 107.9 g / 100 ml
How much PbNO32 will remain undissolved if 500 grams is mixed into a liter of pure water at 40 degree Celsius?
At 40 degrees Celsius, the solubility of Pb(NO3)2 in water is about 228 g/L. Since you are adding 500 grams of Pb(NO3)2 and the solubility limit is 228 g/L, only 228 grams will dissolve, and the remaining 272 grams will stay undissolved.
How much energy is required to raise 1 cubic centimeter of water 1 degree?
It takes 1 calorie of energy to raise 1 gram of water by 1 degree Celsius. Since 1 cubic centimeter of water is equivalent to 1 gram, it would take 1 calorie of energy to raise 1 cubic centimeter of water by 1 degree Celsius.
How much energy is required to raise the temperature of one liter of water 1 degree centigrade?
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
How much heat is required to evaporate 1 liter of water at 100 degree celsius?
The heat required to evaporate 1 liter of water at 100 degrees Celsius is known as the latent heat of vaporization of water, which is approximately 2260 kJ/kg. Since the density of water is about 1000 kg/m³, the heat required would be around 2260 kJ.
What does the prefix calor mean?
Calor is a latin prefix meaning heat. A Calorie is actually a unit of energy based on the energy needed to raise one liter of water one celsius degree
How many watts to heat 1 liter of water?
It takes about 4.18 Joules of energy to heat 1 gram of water by 1 degree Celsius. Therefore, to heat 1 liter (1000 grams) of water by 1 degree Celsius, it would require about 4180 Joules. Converting this to watts depends on the time taken to heat the water.
What will be the temperature of water if 1 liter water of 30 degree Celsius mixes with 1 liter water of 50 degree Celsius?
The final temperature of the water after mixing will be the average of the initial temperatures, which is (30 + 50) / 2 = 40 degrees Celsius.
What are the different units of the metric system and their measure?
meter - length or distance gram - mass liter - volume degree Celsius - temperature calorie - heat newton - force joule - energy
How many Kwh to raise 1 l water 1 degree c?
It takes approximately 1 kilowatt-hour (kWh) of energy to raise 1 liter of water by 1 degree Celsius. This is a common measure of energy for heating water in many applications.
Which has more heat one liter of liquid at 80 degrees Celsius or a ten liter container at 80 degrees Celsius?
The ten liter container at 80 degrees Celsius would have more heat because it has a higher thermal capacity due to its larger volume. Heat is directly proportional to the amount of substance present, so a larger container will contain more heat energy.
How much does a 1.75 liter bottle of smirnoff vodka weigh?
@ 4 degree Celsius it should wait with the empty bottle around 2.3 kg
If you have a 2 liter bottle of liquid water at 0 Celsius. About how many Calories are needed to heat up the water to 100 C?
It takes 1 calorie to heat 1 gram of water by 1 degree Celsius. A 2 liter bottle of water weighs around 2000 grams. Therefore, you would need 200,000 calories to heat the water from 0 to 100 degrees Celsius.
Time required to raise 1 degree centigrade in 1 liter of water?
To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s
