Heat of fusion is absorbed
Q = mLf = 75x 80 = 6000 cal just to melt the ice
Heat is absorbed to change temp
Q = mC(delta)T = 75 x 1 x (90 - 0) = 6750 cal
Total heat = 6000 + 6750 = 12750 calories
The energy needed to completely vaporize a mole of a liquid
No. The quantity of energy required to raise the temperature of water is different depending on the phase of water. This is especially true at or near a phase transition as thermal energy is absorbed during a phase transistion thus altering the amount of energy required to raise the temperature of said water.
The energy required to boil a liquid is dependant on what the liquid is, as every liquid has it's own constant known as a specific heat capacity. This essentially boils down (ha ha) to the strength of the bonds between the molecules, which varies depending on the molecule itself. Water for instance has much stronger intermolecular attractions that, say, liquid nitrogen.
Yes, the heat of vaporization for water is equal in magnitude but opposite in sign to the heat of condensation. This means that the amount of energy required to vaporize water is the same as the amount of energy released when water vapor condenses back into liquid water.
Latent heat is the energy required for 1 kg of a substance to change ___________. phase
The heat required to convert water to steam is known as the latent heat of vaporization. It is around 2260 kJ/kg at standard atmospheric pressure. This energy is needed to break the intermolecular bonds in liquid water and convert it into vapor.
lf = 3.35 x 105 J kg-1 This much amount of heat required to convert 1 kg of ice to liquid Mani.Ra
Heat is required for evaporation to occur as it provides the energy needed to convert liquid water into water vapor. As heat is absorbed by the liquid water, it causes the water molecules to gain enough energy to break free from the liquid state and enter the gas phase. Overall, evaporation is a cooling process as it removes heat from the surrounding environment.
The heat required to convert 20 g of liquid water at 100°C to steam at 100°C is the heat of vaporization of water. This is 2260 J/g. Therefore, the total heat required is 20 g * 2260 J/g = 45200 J. This amount of heat is absorbed by the water as it changes phase from liquid to steam.
To convert ice at 0°C to liquid water at 0°C, 334 J/g of heat is needed (heat of fusion). To raise the temperature of liquid water from 0°C to 55°C, 4.18 J/g°C is required (specific heat capacity of water). The total heat required would be (mass of ice x 334 J) + (mass of ice x 4.18 J/g°C x temperature difference).
The heat required to convert ice at 0°C to water at 0°C is known as the latent heat of fusion. For water, this value is 334 J/g. Therefore, to convert 0.3 g of ice to water at the same temperature, the heat required is 0.3 g * 334 J/g = 100.2 Joules.
Technician A is incorrect. The latent heat of fusion is the amount of heat required to convert a solid into a liquid at its melting point. To convert a liquid to a gas, you would need to add the latent heat of vaporization.
The heat of fusion is used to first convert the volume of liquid to its solid form, then the heat of vaporization is used to convert the solid to vapor. By summing the two energy values, you can calculate the total energy required to vaporize the liquid volume.
The energy required to completely separate the molecules in a liquid and convert them to a gas (boiling), is greater than the energy needed to completely separate the molecules in a solid and convert them to a liquid (melting).
To calculate the heat required to convert ice to liquid at a temperature of 14.7°C, we first need to heat the ice from -12.1°C to 0°C, using the specific heat capacity of ice. Then we calculate the heat required to melt the ice at 0°C to water at 0°C, using the heat of fusion of ice. Finally, we calculate the heat required to heat the water from 0°C to 14.7°C, using the specific heat capacity of water. By performing these calculations, we can determine if the available heat of 4390 J is sufficient.
The simple beginning is that the definition of a calorie is "the energy required to raise the temperature of 1g of water 1°C." Therefore, the energy required to raise 17g of water 32°C: 17*32=544 cal. However, the question asked about ice. There is an extra bit of energy required for the change of physical state. The energy required to convert 1 gram of ice at 0°C to liquid water at 0°C is called the "latent heat" and is equal to about 80 cal. To convert 17g of ice, we multiply this together: 17g * 80cal/g = 1360 cal. So, we add this energy required for the change of state to the energy required to raise the listed quantity to the required temperature and we get 544 cal + 1360 cal = 1904 cal, assuming no heat is lost to the environment. I hope this clarifies some things.
The heat of fusion refers to the energy required to change a substance from a solid to a liquid at its melting point. For water to change from ice to liquid water, heat needs to be added, making the heat of fusion a positive value.