0
What else can I help you with?
How much heat is necessary to vaporize 500 grams of ice at its freezing point?
The heat required to vaporize 500 grams of ice at its freezing point is the sum of the heat required to raise the temperature of the ice to its melting point, the heat of fusion to melt the ice, the heat required to raise the temperature of water to its boiling point, and finally the heat of vaporization to vaporize the water. The specific heat capacity of ice, heat of fusion of ice, specific heat capacity of water, and heat of vaporization of water are all needed to perform the calculations.
How much heat energy will be required to raise the temperature of 15 grams of water 25 degrees c?
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
How many calories are required to raise 8 grams of water 7 degrees Celsius?
The amount of heat needed to raise the temperature of a substance is given by the formula: Q = mcΔT, where Q is the heat (in calories), m is the mass (in grams), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature. Plugging in the values: Q = 8g * 1 cal/g°C * 7°C = 56 calories.
Which process required water to gain 2260 joules of energy per gram?
The process you are referring to is called water having a specific heat capacity of 4.184 J/g°C. This means that it takes 4.184 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius. In this case, to gain 2260 joules of energy, it would take approximately 540.3 grams of water.
How much heat is required to raise temperature of 1 gm of water by 1 c?
The specific heat capacity of water is 4.18 J/g°C. Therefore, it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How much heat is required to raise 2 grams of water 1 degree C?
The answer is 2 calories.
How much heat is necessary to vaporize 500 grams of ice at its freezing point?
The heat required to vaporize 500 grams of ice at its freezing point is the sum of the heat required to raise the temperature of the ice to its melting point, the heat of fusion to melt the ice, the heat required to raise the temperature of water to its boiling point, and finally the heat of vaporization to vaporize the water. The specific heat capacity of ice, heat of fusion of ice, specific heat capacity of water, and heat of vaporization of water are all needed to perform the calculations.
How much heat is required to raise the temperature of 350 grams of water from 22 degrees C?
The specific heat capacity of water is 4.184 J/g°C. To raise the temperature of 350 grams of water from 22°C to a higher temperature, you would multiply the mass of water (350g) by the temperature change and the specific heat capacity of water. So, the heat required would be (350g) x (Tfinal - 22°C) x 4.184 J/g°C.
60 grams of ice will require how many calories to raise th temperature to one degrees Celsius?
A Calorie is defined as the amount energy required to raise 1 gram of water by 1 degree Celsius. 79.7cal are required to a phase change in 1 gram of ice to water. It is being assumed that the temperature of the ice is going to be 0 degrees Celsius, and not any colder. IE, the temperature of the water after its phase change to ice. So, since we have 60 grams of water, it will take (60*79.7) 4782cal just to complete the phase change of ice to water (cause the water to melt). If the ice measured 0 deg. Celsius, it still measures 0 deg. Celsius at this point. Now lets raise it by 1 deg. C. 60 Grams of water * 1 cal/degree C rise = 60 calories are required to raise 60 grams of water by 1 deg. C. 4782cal + 60cal = 4842 calories total to cause 60 grams of ice to phase change into water AND cause the water temperature to rise by 1 degree Celsius.
How much energy is needed to raise the temperature of 2.0 grams of water of 5.0 Celsius?
42 J
How do you calculate the total heat required in kcal to take 70 grams of ice at -29.0 Celsius and convert it to steam at 106 Celsius?
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
How much energy is required to raise 21kg of water by 2 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. To calculate the energy required to raise 21 kg of water by 2 degrees Celsius, use the formula: Energy = mass x specific heat capacity x temperature change. Plugging in the values, the energy required is 21,084 Joules.
What is to raise the temperature of 1 gram of water 1 degree Clntigrade?
Depends on how high you want to raise the gram of water ;).
How much energy is required to raise the temperature of 1 g of water 1 degree Celsius?
Energy required to raise 1 gramme of water by 1 degree C = 1 calorie also, 1 calorie = 4.186 Joules
How much heat energy will be required to raise the temperature of 15 grams of water 25 degrees c?
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
How many calories are required to raise 8 grams of water 7 degrees Celsius?
The amount of heat needed to raise the temperature of a substance is given by the formula: Q = mcΔT, where Q is the heat (in calories), m is the mass (in grams), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature. Plugging in the values: Q = 8g * 1 cal/g°C * 7°C = 56 calories.
How much energy is required to raise water temp 1 degree Celsius?
The amount of energy required to raise the temperature of water by 1 degree Celsius is known as its specific heat capacity. For water, the specific heat capacity is 4.18 Joules/gram°C. This means that it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
