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The process you are referring to is called water having a specific heat capacity of 4.184 J/g°C. This means that it takes 4.184 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius. In this case, to gain 2260 joules of energy, it would take approximately 540.3 grams of water.
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What process requires water to gain 2260 joules energy per gram?
The process that requires water to gain 2260 joules of energy per gram is known as specific heat capacity. Water has a specific heat capacity of 4.18 J/g°C, which means it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Which process requires water to gain 2260 Joulesof energy per gram?
The process of vaporization, where water changes from liquid to gas, requires 2260 Joules of energy per gram to occur.
How much energy is required to heat 955 g of water from 20 degrees C to 100 degrees C?
4.1858 joules of energy will raise the temperature of 1 g of water by 1oC. Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
How many joules are required for boiling 21.1g of water at 100C?
You need o know the initial temperature of water:Heat = specific heat x difference of temperature x mass of water
What is heat of fusion of water to melt ice cube?
The heat of fusion of water, which is the amount of heat energy required to melt one gram of ice at its melting point, is approximately 334 joules per gram. This means that to melt an ice cube, the ice must absorb 334 joules of heat energy per gram to transition from a solid to a liquid state.
What process requires water to gain 2260 joules energy per gram?
The process that requires water to gain 2260 joules of energy per gram is known as specific heat capacity. Water has a specific heat capacity of 4.18 J/g°C, which means it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Latent heat of fusion for H20 ice to water?
334 Joules per gram ... at 0oC, 334 Joules of energy must be added to melt one gram of ice from solid to liquid form, and 334 Joules of energy must be removed to freeze one gram of liquid water to form ice.
How much joules of energy is present in 1 kg of water?
The amount of energy present in 1 kg of water is typically around 4,186,000 joules at room temperature. This value represents the energy required to raise the temperature of 1 kg of water by 1 degree Celsius.
How much energy is required to raise water temp 1 degree Celsius?
The amount of energy required to raise the temperature of water by 1 degree Celsius is known as its specific heat capacity. For water, the specific heat capacity is 4.18 Joules/gram°C. This means that it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams for 0.0?
To calculate the energy required to heat water, you would need to know the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C. Assuming we are heating the water by 1°C, the energy required would be 46.0g * 4.18J/g°C * 1°C = 192.28 Joules.
Which process requires water to gain 2260 Joulesof energy per gram?
The process of vaporization, where water changes from liquid to gas, requires 2260 Joules of energy per gram to occur.
How many joules of energy are removed from 1 gram of water during condensation?
During condensation, approximately 2260 joules of energy are removed from 1 gram of water. This value represents the latent heat of vaporization, which is the energy required to convert water from a liquid to a gas. When water vapor condenses back into liquid water, this amount of energy is released into the surroundings.
As the lake surface freezes in the winter how many joules of heat are realized by each gram of water?
When water freezes into ice, it releases approximately 334 joules of heat per gram. This process is known as the latent heat of fusion, which is the energy required to change water from a liquid to a solid without changing its temperature. Therefore, as the lake surface freezes in winter, each gram of water realizes 334 joules of heat.
How much energy is required to evaporate all the water on Earth?
To evaporate all the water on Earth, approximately 1.2 x 10^21 joules of energy is required. This estimate is based on Earth's total water volume of about 1.386 billion cubic kilometers and the latent heat of vaporization of water, which is around 2.26 million joules per kilogram. This immense amount of energy highlights the significant role water plays in Earth's climate and energy balance.
How much energy is gained by 3 grams of ice when it changes to water?
The energy needed to change ice into water is called the heat of fusion. For ice, this value is around 334 joules per gram. So, for 3 grams of ice, the energy gained when it changes to water would be around 1002 joules (334 joules/gram * 3 grams).
What volume of water can be boiled by 3.0 kg of energy?
To determine the volume of water that can be boiled using 3.0 kg of energy, we first convert the energy from kilograms to joules. Assuming the energy is in kilograms of mass equivalent (using E=mc²), 3.0 kg of energy is equivalent to about 2.7 x 10^16 joules. The energy required to boil water is approximately 2,260 joules per gram (the latent heat of vaporization). Thus, dividing the total energy by the energy needed to boil water gives you about 11,900,000 grams, or approximately 11,900 liters of water.
As the lake surface freezes in the winter how many joules of heat are released by each gram of water?
When water freezes into ice, it releases approximately 334 joules of heat per gram. This process is known as the latent heat of fusion, which is the energy required to change water from a liquid to a solid without changing its temperature. Thus, as the lake surface freezes, each gram of water releases about 334 joules of heat into the surrounding environment.
