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At standard temperature and pressure, one mole of gas takes up 22.4 liters. So the amount of gas necessary to occupy 2 liters is:

2 L ÷ 22.4 mole/L = 0.08929 moles

One mole of oxygen gas (O2) weighs 32 grams per mole, so:

0.08929 moles * 32 g/mole = 2.857 grams of O2

The density of liquid oxygen is 1.141 g/cm³, and so the volume is:

2.857 grams ÷ 1.141 g/cm3 = 2.50 cm3 = 2.50 mL

In other words, oxygen expands by a factor of 800 going from liquid to gas!

See the Related Questions link to the left for more information on solving Ideal Gas Law problems of this type.


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